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wariber [46]
3 years ago
7

An introductory APR is the interest that applies to _____.

Mathematics
2 answers:
mafiozo [28]3 years ago
8 0

Answer: The answer is any combination of purchases, balance transfers and cash advances.

Step-by-step explanation:  An introductory APR rate is defined as follows:

An introductory APR rate is defined as a rate given by credit card issuers to new customers for a particular period. APR rate is very low or most often 0% that applies to any combination of purchases, balance transfers and cash advances depending on the details provided by the by the issuer.

Thus, the answer is  any combination of purchases, balance transfers, and cash advances.

olganol [36]3 years ago
5 0
<span>An introductory APR is the interest that applies to </span>new applicants of a credit card as an incentive to apply for the card; offered by the credit card company.

After the introductory period is over, the APR will go up.
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Evaluate the function below for x=3<br><br> f(x)=2x^3-x^2-4x+9
elixir [45]
Hello,

f(x)=2x^3-x^2-4x+9=(((0+2)x-1)x-4)x+9

f(3)=(((0+2)*3-1)*3-4)*3+9=((2*3-1)*3-4)-3+9=(5*3-4)*3+9=11*3+9=33+9=42

or

f(3)=2*3^3-3^2-4*3+9=2*27-9-12+9=54-12=42

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3 years ago
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What is the y-intercept of the line?<br><br> 1. 0<br> 2. 1<br> 3. -2 <br> 4. 1/2
Nesterboy [21]

Answer:

2. 1

Step-by-step explanation:

the point at which the y axis is passed through is (0,1)

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3 years ago
Anna divided a sheet of paper into 5 equal sections and colored 3 sections blue . What percent is that and it =60
Dimas [21]

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she colored in 60% of the paper blue and left 40% of the paper blank

Step-by-step explanation:

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3 years ago
3x^3-5x+x^7+9+4x^11 polynomial
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The hypotenuse of the right triangle is 5y inches long. The lengths of the legs are x + 8 and x + 3 inches. If the perimeter of
Zolol [24]

Answer: 35 inches.

Step-by-step explanation:

We know that:

hypotenuse = 5*y in

cathetus 1 = (x + 8) in

cathetus 2 = (x + 3) in

The perimeter of the triangle is 76 inches, then:

5*y + (x + 8) + (x + 3) = 76

5*y + 2*x + 13 = 76

We also know that the length of the hypotenuse minus the length of the shorter leg is 17 in.

The shorter leg is x + 3, then:

5*y - (x + 3) = 17

Then we have the equations:

5*y + 2*x + 11 = 76

5*y - (x + 3) = 17

With only these two we can solve the system, first we need to isolate one of the variables in one of the equations, i will isolate x in the second equation.

x = 5*y  - 3 - 17 = 5*y - 20

x = 5*y - 20

Now we can replace this in the other equation, we get:

5*y + 2*x + 11 = 76

5*y + 2*(5*y - 20) + 11 = 76

15*y - 40 + 13 = 76

15*y - 29 = 76

15*y = 76 + 29 = 105

and remember that the hypotenuse is equal to 5*y, then we want to get:

3*(5*y) = 105

5*y = 105/3 = 35

5*y = 35

Then te length of the hypotenuse is 35 inches.

6 0
3 years ago
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