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3 years ago

7

An introductory APR is the interest that applies to _____.

2 answers:

mafiozo [28]3 years ago

8 0

Answer: The answer is any combination of purchases, balance transfers and cash advances.

Step-by-step explanation: An introductory APR rate is defined as follows:

An introductory APR rate is defined as a rate given by credit card issuers to new customers for a particular period. APR rate is very low or most often 0% that applies to any combination of purchases, balance transfers and cash advances depending on the details provided by the by the issuer.

Thus, the answer is any combination of purchases, balance transfers, and cash advances.

olganol [36]3 years ago

5 0

<span>An introductory APR is the interest that applies to </span>new applicants of a credit card as an incentive to apply for the card; offered by the credit card company.

After the introductory period is over, the APR will go up.

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Describe a real-world situation that models the multiplication expression 20(-1).

Brut [27]

Basically you can write taking from something or using something 20 times. Here are three examples.

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3 years ago

The radius of a right circular cone is increasing at a rate of 2 inches per second and its height is decreasing at a rate of 4 i

irina [24]

Answer:

The volume of cone changing at rate $\frac{400}{3}\pi in^3/s$

Step-by-step explanation:

Let r be the radius of cone and h be the height of cone

$\frac{dr}{dt}=2 in/s$

$\frac{dh}{dt}=-4 in/s$

We have to find the rate at which the volume of cone changing when r=10 in and h=20 in

Volume of cone

$V=\frac{1}{3}\pi r^2 h$

Differentiate w.r.t t

$\frac{dV}{dt}=\frac{1}{3}\pi (2rh\frac{dr}{dt}+r^2\frac{dh}{dt})$

Substitute the values

$\frac{dV}{dt}=\frac{1}{3}\pi(2\times 10\times 20\times 2+(10)^2\times (-4))$

$\frac{dV}{dt}=\frac{1}{3}\pi(400)=\frac{400}{3}\pi in^3/s$

Hence, the volume of cone changing at rate $\frac{400}{3}\pi in^3/s$

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Answer:

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