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nevsk [136]
3 years ago
9

How to find the equivalent to 2/5​

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
8 0

Answer:

4/10, 6/15, 8/20, 10/25

Step-by-step explanation:

Those are the fractions equivalent to 2/5

makvit [3.9K]3 years ago
5 0

Answer:

just multiply the denominator and numerator by the same number

Step-by-step explanation:

2/5 x 3= 6/15

equivelent

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Grade 10 Math. Solve for y. Will mark right answer brainliest :)​
Dima020 [189]

Answer:

y=5, y=\frac{38}{11}

Step-by-step explanation:

Hi there!

We are given the equation

\frac{y+2}{y-3}+\frac{y-1}{y-4}=\frac{15}{2} and we need to solve for y

first, we need to find the domain, which is which is the set of values that y CANNOT be, as the denominator of the fractions cannot be 0

which means that y-3≠0, or y≠3, and y-4≠0, or y≠4

\frac{y+2}{y-3} and \frac{y-1}{y-4} are algebraic fractions, meaning that they are fractions (notice the fraction bar), but BOTH the numerator and denominator have algebraic expressions

Nonetheless, they are still fractions, and we need to add them.

To add fractions, we need to find a common denominator

One of the easiest ways to find a common denominator is to multiply the denominators of the fractions together

Let's do that here;

on \frac{y+2}{y-3}, multiply the numerator and denominator by y-4

\frac{(y+2)(y-4)}{(y-3)(y-4)}; simplify by multiplying the binomials together using FOIL to get:

\frac{y^{2}-2y-8}{y^{2}-7y+12}

Now on \frac{y-1}{y-4}, multiply the numerator and denominator by y-3

\frac{(y-1)(y-3)}{(y-4)(y-3)}; simplify by multiplying the binomials together using FOIL to get:

\frac{y^{2}-4y+3}{y^{2}-7y+12}

now add \frac{y^{2}-2y-8}{y^{2}-7y+12} and \frac{y^{2}-4y+3}{y^{2}-7y+12} together

Remember: since they have the same denominator, we add the numerators together

\frac{y^{2}-2y-8+y^{2}-4y+3}{y^{2}-7y+12}

simplify by combining like terms

the result is:

\frac{2y^{2}-6y-5}{y^{2}-7y+12}

remember, that's set equal to \frac{15}{2}

here is our equation now:

\frac{2y^{2}-6y-5}{y^{2}-7y+12}=\frac{15}{2}

it is a proportion, so you may cross multiply

2(2y²-6y-5)=15(y²-7y+12)

do the distributive property

4y²-12y-10=15y²-105y+180

subtract 4y² from both sides

-12y-10=11y²-105y+180

add 12 y to both sides

-10=11y²-93y+180

add 10 to both sides

11y²-93y+190=0

now we have a quadratic equation

Let's solve this using the quadratic formula

Recall that the quadratic formula is y=(-b±√(b²-4ac))/2a, where a, b, and c are the coefficients of the numbers in a quadratic equation

in this case,

a=11

b=-93

c=190

substitute into the formula

y=(93±√(8649-4(11*190))/2*11

simplify the part under the radical

y=(93±√289)/22

take the square root of 289

y=(93±17)/22

split into 2 separate equations:

y=\frac{93+17}{22}

y=\frac{110}{22}

y=5

and:

y=\frac{93-17}{22}

y=\frac{76}{22}

y=\frac{38}{11}

Both numbers work in this case (remember: the domain is y≠3, y≠4)

So the answer is:

y=5, y=\frac{38}{11}

Hope this helps! :)

5 0
3 years ago
Which following relationships would produce a greater output, linear or exponential?
Softa [21]

Answer:

exponential, if you have two groups of data one linear and one exponential eventually the exponential will produce a greater output.

Step-by-step explanation:

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3 years ago
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Pls help me asap will mark brainliest if right
AysviL [449]
Hey! The answer is C.
 
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3 years ago
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I really need some help.........
mel-nik [20]

Answer:its 20400

Step-by-step explanation:

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3 years ago
P is the set of integers that are greater than or equal to -3 a d less than -1
rjkz [21]
To represent this statement I put it in an expression thingy -3 ⩽ p <1
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