What do average mean in math

Two is subtracted from a number, and then the difference is divided by 3. The result is 30. Find the number. Explain how you fou

Soloha48 [4]

I might be bad at explaining or even wrong, but i tried. so here it goes.
2 is subtracted from a number (we'll put N for the missing number) and the difference is divided by 3. so i thought the difference was the final answer so i divided 30 by 3.
my equation came out to 2-n=30/3
so from there i did basic algebra.
i added the N to both sides so i came up with 2=30/3+N (so i wouldn't have a negative variable) and the divided 30/3 so then i had 2=90+N.
still with me? i hope so...
so then i subtracted 90 from both sides to get the variable alone and ended with -88=N.
so if you put N in you get 2-(-88)=30/3
you subtract 2 from -88 and get 90. so now you have 90/3 with equals 30.

4 0

2 years ago

erastovalidia [21]

Answer:

Here we have:

g(x) = 2*√x

And we know that it is related to a parent function, where the parent functions are:

Linear Function: f(x)=x.

Quadratic Function: ݂f(x)=x^2.

Square Root function: f(x)= √x.

Absolute Value function: f(x)=|x|

Cubic function: f(x)=x^3.

Cube Root function: f(x) = ∛x

Logarithmic function: f(x)=log x or f(x)=In x.

Exponential function: f(x) = a^x.

a) Because g(x) = 2*√x

We can see that it is related to the square root function, then the parent function is:

f(x) = √x

b) now we want to write g(x) in terms of f(x)

we have:

g(x) = 2*√x

we can replace √x by f(x)

then we get:

g(x) = 2*f(x)

Now we have g(x) in terms of f(x)

5 0

2 years ago

A book has n consecutive pages torn out. Suppose A is the last numbered page before the torn-out section and B is the first numb

Sergio039 [100]

The answer is n=(a-b)-1 because when you subtract a-b, you get almost the number of pages, but as you are counting the page b which has is not torn out, you must subtract 1 to get the correct answer if you plugged in a variable

8 0

2 years ago

Which graph shows the result of dilating this figure by a factor 1/3 about the origin

nasty-shy [4]

<u>Note:</u> <em>As you have not attached any graph to chose the answer. So, that is I am taking a quadrilateral ABCD as sample figure to clear your concept as it would still clear your concept regarding dilation by a factor 1/3 about the origin.</em>

Answer:

When the quadrilateral ABCD with vertices A(-6, -3), B(-6, 3), C(6, 3) and D(6, -3) respectively is dilated by a factor 1/3 about the origin, the reduced image A'B'C'D' with vertices A(-2, -1), B(-2, 1), C(2, 1) and D(2, -1) is obtained as shown in figure a.

Step-by-step explanation:

Considering the quadrilateral ABCD, as shown in figure a, with the following vertices

A(-6, -3)

B(-6, 3)

C(6, 3)

D(6, -3)

As we know that a dilation is a transformation that generates an image that contains the same shape as the original object, but has a different size.

A dilation that creates a bigger image than the original object is called an enlargement.

A dilation that creates a smaller image than the original object is called an reduction.

If

scale factor $> 1$ , the image will be a stretch or enlargement.

and if

$0$ scale factor , the image will be be a shrink or reduction.

The rule of dilation by a factor 1/3 about the origin:

Dilation with scale factor 1/3, just multiply the coordinates of vertices by 1/3.

$(x, y)$ → $(\frac{1}{3}x, \frac{1}{3}y)$

So,

When the quadrilateral ABCD with vertices A(-6, -3), B(-6, 3), C(6, 3) and D(6, -3) respectively is dilated by a factor 1/3 about the origin, the reduced image A'B'C'D' with vertices A(-2, -1), B(-2, 1), C(2, 1) and D(2, -1) is obtained as shown in figure a.

Therefore,

$(x, y)$ → $(\frac{1}{3}x, \frac{1}{3}y)$

$A(-6, -3)$ → $A'(-2, -1)$