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Reil [10]
3 years ago
14

Which of the following is equal to the expression below? (625•48)1/4

Mathematics
1 answer:
Softa [21]3 years ago
8 0

Answer:

10 4th root of 3

Step-by-step explanation:

The answer is the last one hope this helps

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Kryger [21]
What is Tark
I’m sry I can’t help you

5 0
3 years ago
Help plz <br> If SU = 110, find the value of x. Then find ST and TU.<br> 2x - 10<br> 5x + 50
sergij07 [2.7K]

Answer:

x=10

ST=10

TU=100

Step-by-step explanation:

2x-10 + 5x+50 = 110

2x+5x=110+10-50

7x=70

x=10

2(10)-10

20-10=10

5(10)+50

50+50=100

6 0
3 years ago
A set of middle school student heights are normally distributed with a mean of 150150150 centimeters and a standard deviation of
adell [148]

Answer:

71.57% of student heights are lower than Darnell's height

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 150, \sigma = 20

Darnell has a height of 161.4 centimeters. What proportion of student heights are lower than Darnell's height?

This is the pvalue of Z when X = 161.4.

Z = \frac{X - \mu}{\sigma}

Z = \frac{161.4 - 150}{20}

Z = 0.57

Z = 0.57 has a pvalue of 0.7157

71.57% of student heights are lower than Darnell's height

5 0
3 years ago
MATH HELP PLEASE HELP
sdas [7]

Answer:

75 cm

Step-by-step explanation:

150÷2 = 75

Good luck with your exam :)

5 0
3 years ago
Read 2 more answers
Convert 0.14 to a fraction
Svetradugi [14.3K]
0.14 in fraction form is 7/50
5 0
4 years ago
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