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KIM [24]
3 years ago
12

How can we rewrite 4 - (-9) as an addition problem?

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

Answer:

4 + 9

Explanation:

4 - (-9)

Subtracting a negative is the same thing as adding

4 - (-9) turns into 4 + 9

= 13

Tomtit [17]3 years ago
3 0

So if my ans was helpful u can follow me.

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What are five example recurring decimal<br>​
denpristay [2]

Answer:

These are some examples of recurring decimals.

Definiton:

A repeating decimal or recurring decimal is decimal representation of a number whose digits are periodic (repeating its values at regular intervals) and the infinitely repeated portion is not zero.

8 0
3 years ago
2(3x-9)=5x+2 solve for x
grin007 [14]
You distribute the two in the parenthesis and add both the x and then the 18 and 2 which gives you 20 ;X=20
4 0
3 years ago
Read 2 more answers
Write a quadratic equation in standard form that has a vertex of (-2, 6) and passes through (-4, -2).
Marizza181 [45]

Answer:

The equation of the quadratic in standard form is:

y=-2x^2-8x-2

Step-by-step explanation:

Since they give us the information about where the vertex of the parabola is located, and one extra points where it passes through, we can use the general form of a quadratic in vertex form:

y-y_v=a\,(x-x_v)^2

where (x_v,y_v) is the location of the vertex (in our case the point (-2,6).

Therefore the equation above becomes:

y-y_v=a\,(x-x_v)^2\\y-6=a\,(x-(-2))^2\\y-6=a\,(x+2)^2

Now,we can use the fact that the point (-4,-2) is also a point of the graph, to find the value of the parameter "a":

y-6=a\,(x+2)^2\\-2-6=a\,(-4+2)^2\\-8=a\,(-2)^2\\-8=a\,*4\\a=-2

Then, the equation of the quadratic with such characteristics becomes:

y-6=-2\,(x+2)^2\\y-6=-2x^2-8x-8\\y=-2x^2-8x-2

which is the equation of the quadratic in standard form.

7 0
3 years ago
Help solving this math problem
ladessa [460]

Formula for Mid Point between two points= (x1 + x2)/2, (y1 + y2)/2,

Mid points: SU= (-3,2), TU= (1,0), and ST= (1,2).

<u>Step-by-step explanation:</u>

U = (-3,0)

S= (-3,4)

T= (5,0)

Mid Point Formula= (x1 + x2)/2, (y1 + y2)/2.

With points S(-3,4) and U(-3,0),

Mid point of SU = (-3+(-3))/2, (0+4)/2.

⇒Mid point of SU = (-6/2,4/2).

∴Mid point of SU= (-3,2).

With points T(5,0) and U(-3,0),

Mid point of TU = (5+(-3))/2, (0+0)/2.

⇒Mid point of TU = (2/2,0).

∴Mid point of TU= (1,0)

With points S(-3,4) and T(5,0),

Mid point of ST = (-3+5)/2, (4+0)/2.

⇒Mid point of ST =(2/2, 4/2).

∴Mid point of ST= (1,2)

8 0
4 years ago
Negative 12 plus 44<br> negative 19 plus 61
antiseptic1488 [7]
Your answer would be 74 if you are looking for the answer.
8 0
4 years ago
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