Since these both are on the same hour we'll ignore the 5. We end up having :35 and :52. We'll subtract 35 from 52 which gives us 17. The answer to this is 17 minutes.
The range of F(x) = logb x is True
6 times 11 = 66 because it is 6c. That is your answer. I hope this helps. Could I possibly get brainliest?
(y^2-y-12)/(y^2-2y-15) factor both the numerator and denominator...
(y^2-4y+3y-12)/(y^2-5y+3y-15)
(y(y-4)+3(y-4))/(y(y-5)+3(y-5))
((y-4)(y+3))/((y-5)(y+3)) so the (y+3) terms cancel leaving
(y-4)/(y-5)
