Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
Answer:
Step-by-step explanation:
Recall these rules of logs: log a + log b = log (ab), and log a^b = b log a
Then 3 log q = log q^3 and 6 log v = log v^6, and
log q^3 + 6 log v becomes log q^3 * v^6
Now rewrite this using b as the base:
log q^3 * v^6
b
70000- ten thousand
8000- thousand
000- hundred
00- tens
0- ones
so look at the 7 and if the number on the right is more than 4 you give the ten thousand a new number ; 80000
hope i helped
Let
C=Cynthia's age today
A=Abigail's age today
then
at all times
A=C+8......................(1)
twenty years ago,
A-20=3(C-20)
simplifying
A=3C-40...................(2)
Equate (1) and (2),
C+8=3C-40
8+40=3C-C
C=24
=>
A=32
Check: A-C=8... ok A-20=12 C-20=4 => (A-20)=3(C-20) ...ok
Answer:
Abigail is 32, Cynthia is 24.
