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hram777 [196]
2 years ago
10

Can x = 2i be a "solution" for (x+3)^2 =5

Mathematics
1 answer:
Doss [256]2 years ago
4 0

Answer:

the x =2 cant be a solution for (x+3)^2 =5.

hope it helps.

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We are given with the probabilities P(pepperoni) = 0.7, P(olives) = 0.6, and P(pepperoni or <span>olives) = 0.8. in this case, we are asked to determine  P(pepperoni and olives) that is determined from P(pepperoni) + P(olives) - P(pepperoni or olives) equal then to 0.7 + 0.6 - 0.8 equal to 0.5</span>
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PLEASE I NEED HELP
notka56 [123]

You would transform 5x + 2x into the same term with the associative property, adding like terms. If you subsitute the different values into the expressions you notice that both have a rate of change of 7 like an arithmetic sequence. To see if any value will make the two expressions equal you make them equal to each other.

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faust18 [17]

Answer:

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2 years ago
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I did a trial-and-error solution.

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