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Art [367]
3 years ago
15

Suppose that a main method encounters the statement t3.join(); Suppose that thread t3's run() method has completed running. What

happens?
A. The main method waits for all running threads to complete their run() methods before proceeding.
B. The main method waits for any other thread to complete its run() method before proceeding
C. The main method proceeds to the next statement following the t3.join(); statement
D. Thread t 3 is re-started
E. All threads except t3 that are running are terminated
Computers and Technology
1 answer:
Slav-nsk [51]3 years ago
8 0

Answer:

C. The main method proceeds to the next statement following the t3.join(); statement

Explanation:

join() method allows the thread to wait for another thread and completes its execution. If the thread object is executing, then t3.join() will make that t is terminated before the program executes the instruction. Thread provides the method which allows one thread to another complete its execution. If t is a thread object then t.join() will make that t is terminated before the next instruction. There are three overloaded functions.

join()

join(long mills)

join(long millis, int Nanos)

If multiple threads call the join() methods, then overloading allows the programmer to specify the period. Join is dependent on the OS and will wait .

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Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
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  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

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2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
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  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

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Answer:

3) calcRowAverage:

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  10.                {
  11.                    total = total + arr2D[i][j];
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  14.            }
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  20.        return average;
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Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

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