Approximately how far is the sun from the center of the galaxy?

Physics

1 answer:

Stells [14]4 years ago

6 0

Answer:

About 8 kpc

Explanation:

The milky way galaxy is the galaxy we live in. Its composed of the solar system, billion stars, gas, dust and dark matter.

At its center it contains a super massive black hole called Sagittarius. This object is millions of times as massive as the sun.

The sun is about 8 kpc to the center of the milky way galaxy, this is about 26,000 light years away.

1000 parsecs distance is approximately 3262 light years.

A light year is the distance light can travel in a period of 1 year.

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A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$