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4 years ago

How can you observe the law of conservation of energy in action at the skatepark?

Physics

1 answer:

ivann1987 [24]4 years ago

3 0

Explanation:

When the skater is dropped onto the ramp from above, the potential energy decreases and the kinetic energy increases.

Every time the skater bounces from the impact, thermal energy is gained, and both potential and kinetic energy are lost.

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1. What is the gravitational force between two 4 kilogram masses separated by a distance of 5

Anon25 [30]

Yo, I assumed that this situation occurs on Earth otherwise the answer would be different.

7 0

3 years ago

A light bulb is rated at 25 w when operated at 110 v. how much charge enters (and leaves) the light bulb in 1.0 hour?

DedPeter [7]

According to the current, the charge is 818.18 coulombs.

We need to know about current to solve this problem. Current can be defined as the flow rate of charge through the medium. It can be determined as

I = Q / t

where I is current, Q is charge and t is time.

From the question above, we know that

P = 25 W

V = 110 V

h = 1 hour = 3600 second

Calculate the current

P = V . I

25 = 110 . I

I = 0.23 A

By substituting the given parameters, we can calculate the charge

I = Q / t

0.23 = Q / 3600

Q = 818.18 coulombs

Hence, the charge is 818.18 coulombs.

Find more on current at: brainly.com/question/24858512

#SPJ4

4 0

1 year ago

Jonny tries to ride his bike a little longer each time. Which principle of fitness is he following?

ElenaW [278]

Answer:

Progression

Explanation:

3 0

3 years ago

Read 2 more answers

During normal beating, the heart creates a maximum 3.60 mV potential across 0.250 m of a person's chest, creating a 1.00 Hz elec

grandymaker [24]

Answer:

The maximum electric field strength is 0.0144 V/m.

Explanation:

Given that,

Electric potential created in the heart, V = 3.6 mV

Distance, d= 0.25 m

Frequency of the the electromagnetic wave, f = 1 Hz

We need to find the maximum electric field strength created. We know that the electric potential is given by :

$V=Ed$

E is the maximum electric field strength

$E=\dfrac{V}{d}\\\\E=\dfrac{3.6\times 10^{-3}\ V}{0.25\ m}\\\\E=0.0144\ V/m$

So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.

5 0

3 years ago

Hey can someone help plzzzzz

ohaa [14]

Answer:

Potential Energy stored = mgh ; m : mass, g : gravitational acceleration (let 10m/s) , h : height

Hence,

Energy Stored in the ball = mgh = (2*10*4) J

= 80 Joules!

8 0

3 years ago

Read 2 more answers