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stich3 [128]
3 years ago
6

which of following categories of small bodies in the solar system does ceres belong to?. . . A.Dwarf Planets. B.Comets. C.Astero

ids. D.Planets
Physics
2 answers:
FromTheMoon [43]3 years ago
6 0
I suggest you to choose A. as ceres belong to Dwarf Planets.
olchik [2.2K]3 years ago
5 0
The category of small bodies that the solar system Ceres belongs to is the Dwarf Planets. The correct answer is A, dwarf planets.
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a merry go round has a radius of 8 meters makes 2 revolutions every 2.5 minutes. A. express the angular speed of the merry go ar
pantera1 [17]

Answer:

a).v=83.77x10^{-3} rad/s

b).v=0.8rpm

c).v=0.5865 m/sec.

Explanation:

Given:

r=8m

v=\frac{2rev}{2.5minutes}

a).

2 rev*\frac{2\pirad}{1rev}=4\pi  rad

t=2.5minutes*\frac{60s}{1minute}=150s

The angular speed in radians per seconds is

v=\frac{4\pi}{150s}=83.77x10^{-3} rad/s

b).

v=\frac{2rev}{2.5minute}rpm

v=0.8rpm

c)

Child's distance per revolution

(pi*2r) = 43.988 metres.  

v=(43.988 x 0.0133333) = 0.5865 m/sec.

4 0
3 years ago
Find the mass of a 165 N child
Alexeev081 [22]

Answer:

F=ma

165=m*9.8

m=16.6kg

8 0
2 years ago
Newtons prism experiments showed that white sunlight is made up of
DanielleElmas [232]
All the colors of the visible spectrum
4 0
3 years ago
Read 2 more answers
A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glas
ohaa [14]

Answer:

ΔP = (640 N/cm^2)

Explanation:

Given:-

- The volume increase, ΔV/V0 = 4 ✕ 10^-3

- The Bulk Modulus, B = 1.6*10^9 N/m^2

Find:-

Calculate the force exerted by the moonshine per square centimeter

Solution:-

- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.

                                  B = ΔP / [(ΔV/V)]

- Now rearrange the above relation and solve for ΔP or force per unit area.

                                  ΔP = B* [(ΔV/V)]

- Plug in the values:

                                  ΔP = (1.6*10^9)*(4 ✕ 10^-3)

                                  ΔP = 6400000 N/m^2

- For unit conversion from N/m^2 to N/cm^2 we have:

                                  ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2

                                  ΔP = (640 N/cm^2)

7 0
3 years ago
AYUDAAA PORFAVOR
Sholpan [36]

Queremos crear un diagrama general para calcular el área de un triangulo.

Este será algo como:

  1. Definir variables
  2. Pedirle al usuario que introduzca los valores deseados (de las variables).
  3. Leer los valores deseados y asignarlo a la variable correspondiente.
  4. Realizar la operación para calcular el área.
  5. Mostrar en pantalla el resultado.

Como naturalmente habra algunas variaciones segun el programa que utilicemos, lo voy a escribir de forma bastante general.

Primero definamos nuestras variables:

Por ejemple, en fortran usariamos algo como:

real:: B, H, A

Donde B será la variable que usaremos para la base, H para la altura, y A para el área.

Luego tenemos que escribir en pantalla algo que le diga al usario que debe introducir la base y el area.

Luego el programa debe ser capaz de leer ese input.

con algo de la forma:

B = read*input 1

H = read*input 2

Una vez tenemos definidas las variables, simplemente calculamos el área del triangulo:

A = H*B/2

Finalmente la podemos mostrar en pantalla con algo como:

print(A).

Lo que nos mostraría el valor del área.

Concluyendo, el diagrama en general sería:

  1. Definir variables
  2. Pedirle al usuario que introduzca los valores deseados (de las variables).
  3. Leer los valores deseados y asignarlo a la variable correspondiente.
  4. Realizar la operación para calcular el área.
  5. Mostrar en pantalla el resultado.

Si quieres aprender más, puedes leer:

brainly.com/question/21949109

5 0
2 years ago
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