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stich3 [128]
3 years ago
6

which of following categories of small bodies in the solar system does ceres belong to?. . . A.Dwarf Planets. B.Comets. C.Astero

ids. D.Planets
Physics
2 answers:
FromTheMoon [43]3 years ago
6 0
I suggest you to choose A. as ceres belong to Dwarf Planets.
olchik [2.2K]3 years ago
5 0
The category of small bodies that the solar system Ceres belongs to is the Dwarf Planets. The correct answer is A, dwarf planets.
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How is the Maunder minimum related to climate?
Alexxandr [17]

Maunder minimum is related to climate due to the unusually low sunspot activity correlates to unusually cold climatic events. The answer is letter A. It happened around 1645 and 1715 and also coincided with the phenomena ‘Little Ice Age’ (1500 – 1850) in the Northern Hemisphere.

7 0
3 years ago
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What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise mas
LenKa [72]

<em>The correct option is </em><em>A</em>. The information we know about the known exoplanets is estimates of orbits and masses.

<h3>What is exoplanets?</h3>

An exoplanet or extrasolar planet is a planet outside the Solar System.

In other words, exoplanet is any planet beyond our solar system.

<h3>Characteristics of exoplanets</h3>

exoplanets are known for the following characteristics;

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Thus, the information we know about the known exoplanets is estimates of orbits and masses.

Learn more about exoplanets here: brainly.com/question/1514493

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5 0
2 years ago
A 10 kg mass rests on a table. What acceleration will be generated when a force of 5 N is applied? a 0.5 m/s2 b 3.5 m/s2 c 5 m/s
rosijanka [135]

Answer:

a= 0.5m/s^2

Explanation:

Force applied on an object is known as

F=m.a  (Newton's second law states it)

a=F/m

a=5/10=0.5m/s^2

3 0
3 years ago
When you are riding in a car then the driver suddenly steps on the gas pedal, why do you feel a jolt and push back?
inessss [21]

Answer:

due to acceleration lol

4 0
3 years ago
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A sample of carbon dioxide (C°p,m = 37.11 J K−1 mol−1) of mass 2.80 g at 27°C is allowed to expand reversibly and adiabatically
My name is Ann [436]

Answer:

182 to 3 s.f

Explanation:

Workdone for an adiabatic process is given as

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

where γ = ratio of specific heats. For carbon dioxide, γ = 1.28

For an adiabatic process

P₁V₁ʸ = P₂V₂ʸ = K

K = P₁V₁ʸ

We need to calculate the P₁ using ideal gas equation

P₁V₁ = mRT₁

P₁ = (mRT₁/V₁)

m = 2.80 g = 0.0028 kg

R = 188.92 J/kg.K

T₁ = 27°C = 300 K

V₁ = 500 cm³ = 0.0005 m³

P₁ = (0.0028)(188.92)(300)/0.0005

P₁ = 317385.6 Pa

K = P₁V₁¹•²⁸ = (317385.6)(0.0005¹•²⁸) = 18.89

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

V₁ = 0.0005 m³

V₂ = 2.10 dm³ = 0.002 m³

1 - γ = 1 - 1.28 = - 0.28

W =

18.89 [(0.002)⁻⁰•²⁸ - (0.0005)⁻⁰•²⁸]/(-0.28)

W = -67.47 (5.698 - 8.4)

W = 182.3 = 182 to 3 s.f

7 0
3 years ago
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