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stich3 [128]
3 years ago
6

which of following categories of small bodies in the solar system does ceres belong to?. . . A.Dwarf Planets. B.Comets. C.Astero

ids. D.Planets
Physics
2 answers:
FromTheMoon [43]3 years ago
6 0
I suggest you to choose A. as ceres belong to Dwarf Planets.
olchik [2.2K]3 years ago
5 0
The category of small bodies that the solar system Ceres belongs to is the Dwarf Planets. The correct answer is A, dwarf planets.
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The Answer is A. Volume
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Which of the following are vector quantities?
oksano4ka [1.4K]

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Displacement and acceleration

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The cytoplasm is the watery fluid found within cells. The cytoplasm holds all of the organelles, except _______, in place within
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The cytoplasm holds all the organelles, except the nucleus.

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4 0
3 years ago
A 150-newton force, applied to a wooden crate at an angle of 30° above the horizontal, causesthe crate to travel at constant vel
omeli [17]

Answer:

Explanation:

A component of 150 N in vertical direction will reduce the magnitude of reaction force.

reaction force exerted by the floor

= mg - 150 sin 30

where m is mass of the crate .

the magnitude of the horizontal component of the 150-newton force

150 cos30

= 130 N

This force tries to pull the crate in forward direction with acceleration but it has no acceleration . It is so because frictional force of equal magnitude acts on it in opposite direction which makes the net force acting on it equal to zero.

Hence frictional force is equal to 150 cos 30.

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3 0
3 years ago
A brass alloy is known to have a yield strength of 240 MPa (35,000 psi), a tensile strength of 310 MPa (45,000 psi), and an elas
Karo-lina-s [1.5K]

Answer:

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

Explanation:

Given that

Yield strength ,Sy= 240 MPa

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L=380 mm

ΔL = 1.9 mm

Lets find strain:

Case 1 :

Strain due to elongation (testing)

ε = ΔL/L

ε = 1.9/380

ε = 0.005

Case 2 :

Strain due to yielding

\varepsilon' =\dfrac{S_y}{E}

\varepsilon' =\dfrac{240}{110\times 1000}

ε '=0.0021

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

For computation of load strain due to testing should be less than the strain due to yielding.

4 0
3 years ago
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