Answer:
Explanation:
The internet could be regarded has a marketplace or platform which gives individuals, businesses the opportunity to interact, relate, access opportunities, learn in an easy manner with the help of a data connection. The internet has redefined the process and concept of acesing information and interaction with the ease and coverage it brings. The Social media is could be seen a part of the internet platform which allows people to relate and interact, make friends, promote brands and so on. The internet and social media platforms however, in spite of its huge benefits comes with its inherent risk. Including the surge in cyber crime, immorality and information theft to mention a few. Common scenarios whereby banking details are being stolen from databases resulting in wholesale illegal transfer of funds. Issues of blackmail and violent defamation by groups of cohorts has also been a con in the advent of internet and social media, including growing trends of fake news which usually escalate tension, in which the recent unrest in my vicinity benefitted negatively from.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
D. Rasterize
This answer makes the most since
Answer:
false
Explanation:
i believe the right term is error