Teenagers and their parents will never understand each other-the generation gap is too big. Its for my grade 11 English speech

The game begins with the player having 20 POINTS

kompoz [17]

Answer:

Following are the code to this question:

import random#import package for using random method

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

dice1 = random.randint(1,6)

dice2 = random.randint(1,6)

return dice1 + dice2

def rolling(): # defining method rolling

n_roll = 0 # defining num variable that initial value that is 0.

p = 20 # defining variable p for looping, that points in between 1 and 59

while p > 0 and p < 60: # defining loop that counts value dice value two times

d = rolling_dice()#defining d variable that hold method value

n_roll+= 1 #defining n_roll that increment n_roll value by 1

if d == 7 or d == 11:# defining if block that uses the d variable that checks either 7 or 11, player won d in p variable

p+= d # use p variable that adds d variable

elif d == 2 or d == 3 or d == 12:#defining elif block to that checks d variable by using or operator

p-= d#defining d variable that decreases d variable variable

else: # defining else block

p1 = d # using p1 variable that store d value

while True:# defining loop that calculates values

d = rolling_dice()#defining d variable that holds method values

n_roll += 1 #increment the n_roll value by 1

if d == 7:#defining if block that checks d value equal to 7

p -= p1#subtract the value of p1 in p variable

break # exit loop

elif d == p:#defining elif block to check d value is equal to p

p += p1#adds the value of p1 in p variable

break#using break keyword

if p<= 0:#defining if block that checks p-value is less then equal to 0

print('Player lost')#using print method

elif p>= 60:#defining else block that checks p-value is greater than equal to 60

print('Player won')#using print method to print the value

print('number of dice rolls:', n_roll)#use print method to print n_rolls value

rolling()

Output:

Player lost

number of dice rolls: 38

Explanation:

In the above-given python code, a method "rolling_dice" is declared, inside the method two-variable "dice1 and dice2" is declared, that uses the random method to calculate the value in both variable and use the return keyword to add both values.

In the next step, another method the "rolling" is declared, inside the method "n_roll and p" is declared that assigns the values and use the two while loop, inside the loop if block is defined that calculates the values.
In the next step, a condition block is used that stores value in the p variable and use the print method to print the "n_roll" value.

8 0

3 years ago

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

3 years ago

What is transmission control protocol?

xz_007 [3.2K]

Answer:

it is a connection-oriented communications protocol that facilitates the exchange of messages between computing devices in a network.

Explanation:

3 0

3 years ago

What is a non-example of job outlook.

Papessa [141]

Answer:

Before you choose a career you should find out what its job outlook is. ... employed in a particular occupation over a set period, for example, two years, five years or ... 2% and 4%); Have little or no change (a decrease or increase of 1% or less) .

Explanation:

4 0

2 years ago

Given the macro definition and global declarations shown in the image below, provide answers to the following questions:

galben [10]

Answer:

A. 243

B. True

C. 0

Explanation:

Macro instruction is a line of coding used in computer programming. The line coding results in one or more coding in computer program and sets variable for using other statements. Macros allows to reuse code. Macro has two parts beginning and end. After the execution of statement of quiz4 x, 4 the macro x will contain 243. When the macro is invoked the statement will result in an error. When the macro codes are executed the edx will contain 0. Edx serve as a macro assembler.

4 0

3 years ago

Teenagers and their parents will never understand each other-the generation gap is too big. Its for my grade 11 English speech​

Teenagers and their parents will never understand each other-the generation gap is too big. Its for my grade 11 English speech