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Greeley [361]
3 years ago
7

In the coordinate plane, the x axis (y=0) and y axis (x=0) are perpendicular. The product of the slopes of two perpendicular lin

es is -1. Explain why this definition does not apply to the lines y=0 and x=0.
Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

see the explanation

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

In the coordinate plane, the x axis (y=0) and y axis (x=0) are perpendicular

however

this definition does not apply to the lines y=0 and x=0.

because

The slope of the horizontal line y=0 is equal to zero and the slope of the vertical line x=0 is undefined

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Answer:

13655.90016

Step-by-step explanation:

8.4^3 \times 4.8^2 \\= 592.704 \times 23.04\\=13655.90016

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After flying between two black holes, our engines have been a bit janky. The probability of one of any of our 8 power couplings
otez555 [7]

Answer:

Step-by-step explanation:

We would apply the formula for binomial distribution. It is expressed as

P(x = r) = nCr × q^(n - r) × p^r

Where

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From the information given,

p = 10% = 10/100 = 0.1

q = 1 - q = 1 - 0.1 = 0.9

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P(x = 0) = 0.43

2) The probability that one fails is

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P(x = 1) = 0.38

3) The probability that four fails is

P(x = 4) = 8C4 × 0.9^(8 - 4) × 0.1^4

P(x = 4) = 0.0046

3) The probability that six fails is

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3 years ago
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Hmm, (x,y)
x is horizontal or left right
y is vertical or up down


so

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2nd and 3rd
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