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SashulF [63]
3 years ago
10

Mrs.Tong is baking brownies for a school party.The

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

D 5:1

Step-by-step explanation:

45 brownies

9 eggs  

brownies to eggs

45:9

simplify 45/9 using the common denominator which is 9 divide numerator and denominator which equals 5:1

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A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo
r-ruslan [8.4K]

Answer: a) Length of wire to replace old one=9ft

b) Length of wire=3.09ft

Leftover wire=0.91ft

Step-by-step explanation: from the right angle triangle, Tan&=20/15

&=53.13°

Length of wire,x=cos 31.13=x/15

15cos31.13

X=9

b) Tan&=10/6

Tan^-110/6

&=59.05

Length= 6cos59.04

X=3.09

4-3.09=.91= leftover wire

8 0
3 years ago
Jenny is having a party. She has one
Slav-nsk [51]
2........:)good luck
8 0
3 years ago
What is the product of 2x - 5 and 3x2 + 5x - 7? Write your answer in standard form.
Orlov [11]

Answer:

(2x - 5 ) (3x^2 + 5x - 7) = 6x^3 - 5x^2 - 39x - 35

The product of 2x – 5 and 3x2 + 5x - 7equal to the product of 5x - 2 and 3x2 + 5x - 7 are not equal.

Step-by-step explanation:

Product means multiplication

Product of 2x - 5 and 3x^2 + 5x - 7

(2x - 5 ) (3x^2 + 5x - 7)

= 6x^3 + 10x^2 - 14x - 15x^2 - 25x - 35

Collect like terms

= 6x^3 + 10x^2 - 15x^2 - 14x - 25x - 35

= 6x^3 - 5x^2 - 39x - 35

Product of 5x - 2 and 3x^2 + 5x - 7

(5x - 2) (3x^2 + 5x - 7)

= 15x^3 + 25x^2 - 35x - 6x^2 - 10x + 14

Collect like terms

= 15x^3 + 25x^2 - 6x^2 - 35x - 10x + 14

= 15x^3 + 19x^2 - 45x + 14

The product of 2x – 5 and 3x^2 + 5x - 7equal to the product of 5x - 2 and 3x^2 + 5x - 7 are not equal.

They both consist of different variables in their multiplier

8 0
3 years ago
UJ 1641"
Alekssandra [29.7K]

Answer:

t

Step-by-step explanation:

7 0
3 years ago
Multiply the numbers and simplify the answer: 3 x 1- 3/4
madam [21]
\underbrace{3\times1}_{first}-\frac{3}{4}=3-\frac{3}{4}=2\frac{1}{4}

3\times1\frac{3}{4}=3\times\frac{1\times4+3}{4}=3\times\frac{4+3}{4}=\frac{3}{1}\times\frac{7}{4}=\frac{3\times7}{4}=\frac{21}{4}=\frac{20+1}{4}=\frac{20}{4}+\frac{1}{4}\\\center\boxed{=5\frac{1}{4}}
5 0
3 years ago
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