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NARA [144]
3 years ago
9

hydrogen and oxygene react to form water l. How many molecules of O2 are required to produce 0.6 of H20​

Chemistry
1 answer:
user100 [1]3 years ago
8 0

Answer:

It is required 0.3 molecules of O2 to produce 0.6 molecules of H2O

Explanation:

The water´s formation reaction is: 2H2 + O2 --> 2H2O

This reaction shows the molecular O2:H2O ratio: 1:2.

Then, if we want to know how many molecules of O2 are required to produce 0.6 of H20​, it is necessary calculate as it showed next:

0.6 molecules H2O * (1 molecula O2 / 2 molecules H2O)= 0.3 molecule O2

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(this is what I used)

6 0
3 years ago
A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
Vlad1618 [11]
To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = <span>10130.0 kPa
</span>V is the volume of the gas = 50 liters
n is the number of moles that we want to calculate
R is the gas constant = <span>8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
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506500 = 4763.922 n
n = </span>506500 / 4763.922
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7 0
4 years ago
Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?
sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

density=\frac{mass}{volume}

Now, density of isooctane = 0.692 g/mL

Volume  = 3.8 gal

Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

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As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

Volume in mL = 14364 mL

Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

m = 0.692 g/mL\times 14364 mL

= 9939.888 g

Hence, mass of 3.8 gal of the gasoline is 9939.888 g.



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Answer:

I don't know the ans please search on the Google you will get

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