The compound : C₄₀H₄₄N₄O
<h3>Further explanation</h3>
The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
• Determine the mass ratio of the constituent elements of the compound.
• Determine the mole ratio by dividing the percentage by the atomic mass
The mol ratio of composition : C : H : N : O
Answer:5.309 × 10²⁴ atoms.
Explanation:
Given that
molar mass of NH3 = 17
g/mol
Mass of NH3 = 5g
Therefore, No of moles of NH3 = Mass/ molar mass
= 5g/ 17g/mol
= 0.294 moles.
I mole = 6.02 × 10²³ atoms
Therefore the number of hydrogen atoms in a 0.294 moles of ammonia gives us
0.294× 6.02 × 10²³ × 3 ( since there are 3 hydrogens in Ammonia )
= 5.309 × 10²⁴ atoms.
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<span>Chlorofluorocarbons (CFCs) can damage the ozone layer.</span>
