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Lelechka [254]
3 years ago
10

2. Calculate the density of a liquid in a beaker. The beaker has a mass of 15 grams when empty. The beaker plus an unknown liqui

d has a mass of 64 grams. What is the density (g/ml) of the liquid if its volume is 10. mL?
Chemistry
1 answer:
Pie3 years ago
5 0

Answer:

The density of the liquid is 4.9 g/ml

Explanation:

Density of a liquid is usually measured by filling a beaker of known weight and known capacity (total volume in ml you can fill it) and weighing it. The difference between the total weight (beaker+liquid) and the beaker weight is the liquid weight. Finally, you must divide <em>liquid weight/volume</em> to obtain density.

For the problem:

beaker=15 g

beaker+liquid=64 g

⇒liquid= 64 g - 15 g = 49 g

density= \frac{mass}{volume} = \frac{49 g}{10 ml} = 4.9 g/ml

You might be interested in
How many moles of h2o are equivalent to 97.3 grams of h20
g100num [7]

Answer : 5.405 moles of H_2O are equivalent to 97.3 grams of H_2O

Solution : Given,

Mass of H_2O = 97.3 g

Molar mass of H_2O = 18 g/mole

Formula used :

\text{ Number of moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}

or,

\text{ Number of moles of }H_2O=\frac{\text{ Given mass of }H_2O}{\text{ Molar mass of }H_2O}

Now put all the given values in this formula, we get the moles of H_2O

\text{ Number of moles of }H_2O=\frac{97.3g}{18g/mole}=5.405moles

Therefore, 5.405 moles of H_2O are equivalent to 97.3 grams of H_2O

6 0
3 years ago
What makes a gas a gas?
Grace [21]

Answer:

Gas is one of the four fundamental states of matter (the others being solid, liquid, and plasma). A pure gas may be made up of individual atoms (e.g. a noble gas like neon), elemental molecules made from one type of atom (e.g. oxygen), or compound molecules made from a variety of atoms (e.g. carbon dioxide).  

Explanation:

5 0
2 years ago
Read 2 more answers
Which is not a characteristic of a compound?
shusha [124]
The second answer is not a characteristic because compounds don’t vary from sample to sample. For example NaCl (table salt) is indistinguishable from sample to sample.
4 0
2 years ago
The reaction converting glycerol to glycerol-3-phosphate (energetically unfavorable) can be coupled with the conversion of ATP t
Brut [27]

Answer:

glycerol-3-phosphate, ADP, H⁺

Explanation:

The reaction of converting glycerol to glycerol-3-phosphate which makes is unfavorable and is coupled with the second reaction which involves conversion of ATP to ADP which is high energetically favorable.

Reaction 1:  Glycerol + HPO₄²⁻ ⇒ Glycerol-3-phosphate + water

Reaction 2:             ATP  + H₂O ⇒ ADP + HPO₄²⁻ + H⁺

The coupled reaction of both the reactions become favorable. Thus, the overall coupled reaction is:

<u>Glycerol + ATP ⇒ Glycerol-3-phosphate + ADP + H⁺</u>

The net products are = glycerol-3-phosphate, ADP, H⁺

8 0
3 years ago
The principal component of mothballs is naphthalene, a compound with a molecular mass of about 130 amu, containing only carbon a
DIA [1.3K]

Answer:

Empirical formula = C5H4

Molecular formula = C10H8

Explanation:

When the 3000 mg of naphthalene are burned they produce 10.3 mg of CO2. Knowing the unbalanced equation of the combustion of naphthalene, we have:

CxHy + O2 = CO2 + H2O

We calculate the molar composition of the sample. We look for the molecular weights in the periodic table:

CO2 = 12,011 + 2 (15,999) = 44,009 g

Mol C = 10.3 mg * (1 mol CO2 / 44.009 g CO2) * (1 mol C / 1 mol CO2) = 0.234 mmol C

Mass C = 0.234 mmol C * (12.011 g C / 1 mol C) = 2.8105 mg C

Mass H = 3 mg - 2.8105 mg = 0.1895 mg H

Mol H = 0.1895 mg H * (1 mol H / 1,008 g H) = 0.188 mmol H

To calculate the empirical formula, we must divide the number of moles of each element by the smallest number of moles, in this case, of hydrogen:

C = 0.2340 mmol C / 0.1895 mol H = 1.25

H = 0.1895 mmol H / 0.1895 mmol H = 1

We multiply the coefficients by 4, and we have the empirical formula:

C1.25 * 4H1 * 4 = C5H4

The molecular formula is equal to (C5H4)m, where m is calculated by the molecular and empirical mass ratio, as follows:

Empirical mass = (5 * 12.011) + (4 * 1.008) = 64.09 g

m = 130 g / 64.09 g = 2.02 = 2

Therefore we have the molecular formula:

(C5H4)2 = C10H8

4 0
3 years ago
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