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Anika [276]
2 years ago
9

Lisa says that 43 is a 2 - digit odd number that is a composite. is she correct? explain

Mathematics
2 answers:
klemol [59]2 years ago
8 0
No, she is not correct.

A "composite" is a number that can be divided evenly (no decimals) by something other than itself (43) and 1.

43 has no other numbers that can divide into it and leave it a whole number.
soldi70 [24.7K]2 years ago
5 0
Arewar Virtuoso is right because 43 can not divide with anything but 1 & itself (43)!!!!
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Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) < 0, csc (t) &
Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as \sin (t) \ne 0,

\displaystyle \csc t = \frac{1}{\sin t}.

Therefore, \csc(t) > 0 is equivalent to \sin (t) > 0.

Consider a unit circle centered at the origin. If the terminal side of angle t intersects the unit circle at point (x,\, y), then

  • \cos (t) = x, and
  • \sin(t) = y.

For angle t,

  • x = \cos(t) < 0, meaning that the intersection is to the left of the y-axis.
  • y = \sin(t) > 0, meaning that the intersection is above the x-axis.

In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0
2 years ago
HELP ASAP
Ivan

Answer:

Good Luck!

Step-by-step explanation:

5 0
3 years ago
PLZ help 50 points and brainleist Which expression shows the result of applying the distributive property to −2(1/3 x− 1/5)
CaHeK987 [17]

Answer:

the answer is A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
You can represent an odd integer whith the expression 2n+1, where n is any integer . Write and solve an equation to find three c
oksian1 [2.3K]
Any odd number can be expressed by 2n+1.

For example,  

2n+1=111
2n=110
n=110/2=55

means that 111 is 2n+1 for n=55


Thus if an odd number is 2a+1, the next few numbers are as follows:

2a+1, 2a+2, 2a+3, 2a+4, 2a+5

So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.


Back to our problem: 

three consecutive odd numbers whose sum is 63 are:

(2n+1)+(2n+3)+(2n+5)=63

6n+9=63

6n=63-9=54

n=54/6=9


2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23


Answer: 19, 21, 23



5 0
3 years ago
Help in class and I really need help
Vanyuwa [196]
I think the answer is the third one
8 0
2 years ago
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