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alex41 [277]
3 years ago
14

0.25555555 as a fraction

Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

23/90

Step-by-step explanation:Sorry if it's wrong!!!

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SUPER EASY MATH PROBLEM IM JUST DUMB, WILL MARK BRAINLIEST. PLEASE HELP
worty [1.4K]

Answer:

m<1 = 105°

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Read 2 more answers
The faces of a tetrahedron die are numbered 1 to 4. if each of the 4 sides is equally likely to land down, what is the probabili
Hoochie [10]

The probability distribution for the face landing down =  4/15

<h3>What is the probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

<h3>According to the given information:</h3>

If we assign 1 probability x

then 2 has probability  1/2 x.

Similarly,

then 3 has probability = 1/2((1/2)*x) = (1/4)*x

so

then 4 has probability = 1/2((1/4)*x) = (1/8)*x

These probabilities need to sum to 1.

Hence:

                x+\frac{1}{2} x+\frac{1}{4} x+\frac{1}{8} x=1

or equivalently

                   (15/8)*x = 1

                       x = 8/15

the probability distribution for the face landing down  = (1/2)*(8/15)

                                                                                         = 8/30

                                                                                         =  4/15

To know more about probability visit:

brainly.com/question/1581057                  

#SPJ4

I understand that the question you are looking for is:

A tetrahedral die has four faces, numbered 1-4. If the die is weighted in such a way that each number is twice as likely to land facing down as the next number (1 twice as likely as 2, 2 twice as likely as 3, and so on) what is the probability distribution for the face landing down?

7 0
1 year ago
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