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stepladder [879]
4 years ago
5

F(x)=-6x-8, what if f(-3)

Mathematics
1 answer:
Westkost [7]4 years ago
4 0

Answer:

f(-3) = 10

Step-by-step explanation:

Simply plug in x as -3 to find f(-3):

f(-3) = -6(-3) - 8

f(-3) = 18 - 8

f(-3) = 10

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Find the 13th term in the following<br> arithmetic sequence :<br> 2, 10, 18, 26, ...
kondor19780726 [428]

Answer:

98

Step-by-step explanation:

This is an arithmetic sequence

The common difference is 10-2 =8

a1 = 2

an = a1+d(n-1)

an = 2+8(n-1)

we want the 13th term

a13 = 2 +8(13-1)

      =2+ 8*12

     = 2+96

     = 98

8 0
4 years ago
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How do I do this???????
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Answer:

42

Step-by-step explanation:

alternate exterior angles are equal. Therefore 32 = y - 10. Solving for y:

y - 10 = 32

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3 years ago
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5 0
3 years ago
In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?
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Answer:

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And  Cos B = \frac{CB}{AB}.

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

                               Hypotenuse = AB\\Base = CB\\Perpendicular = AC

So,                            Sin\theta = \frac{perpendicular}{hypotenuse}

                                SinB = \frac{AC}{AB}

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

                               SinA= \frac{CB}{AB}

Again,                    Cos\theta= \frac{base}{hypotenuse}

Then,                    CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

Hence,

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

                               

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4 years ago
Can someone please help me on this
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it is a because it is the line is in the spot we're it is ststop to go

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