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e-lub [12.9K]
3 years ago
9

1. Scale: 1 inch to 20 miles. How many inches would represent 80 miles?

Mathematics
1 answer:
Katarina [22]3 years ago
3 0

Answer:

4 inches

Step-by-step explanation:

Your scale: 1 inch=20 miles

80 miles/20 miles=4

80 miles is equal to 4 inches on the scale.

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A rectangular prism has a length of 7 inches and a width of 5 inches. The lateral area is 192 square inches. What is the height
Dennis_Churaev [7]

Answer:

I think it would be 5.49 as the height of the prism.

Step-by-step explanation:

I just did 7 × 5 which is 35, and then I did 192 ÷ 35 and got 5.49. I'm not completely sure but that's my best answer I hope it helps!

6 0
3 years ago
Read 2 more answers
PLEASE HURRY I NEED YOUR HELP! show work
8090 [49]

Answer:

1) 10

- 3 3/8

________

=6 5/8

2)  1/5= 2/10

2/10

+ 20 3/10

+ 5 6/10

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25 11/10

= 26 1/10

3) 11/12

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5 0
4 years ago
The greater of two consecutive EVEN numbers is 40 less than twice the smaller number. Find the larger number
Bas_tet [7]

Answer:

<h3>           44</h3>

Step-by-step explanation:

z -  some integer

2z - first given even integer (the smaller one)

2z+2 - even integer consecutive to 2z  (the larger one)

2(2z)    - twice the smaller number

2(2z) - 40    - the number 40 less than twice the smaller number

2(2z) - 40 = 2z + 2

4z - 40 = 2z + 2

2z = 42

 

2z+2 = 42+2 = 44

check:

2(2z)-40 = 2(42)-40 = 84-40 = 44

3 0
3 years ago
Tia invests $2,500 at an interest rate of 4%, compounded quarterly, and another $2,500 at an interest rate of 3.75%, compounded
Radda [10]
I’m pretty sure the answer is A I hope that helps :)
5 0
3 years ago
The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of
Lunna [17]

Answer:

Change in area=24\pi-48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square=s^{2}

Area of circle=\pi r^{2}

Area enclosed=(\pi  r^{2})-s^{2}

dA/dt=2\pir(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2(\pi)(6)(2)-2(24)(1)

Change in area=24\pi-48

6 0
3 years ago
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