Answer:
.
Explanation:
The average speed of an object is equal to total distance over total time.
- Distance traveled:
.
How much time is taken? This trip is divided into two halves, each of distance 
.
Time spent on the first half of the trip:
.
Similarly, time spent on the second half of the trip:
.
In total:
.
Average speed:
.
This value turned out to be slightly different from the average of the speed during the two halves of the journey. The reason is that the object traveled at each speed for a different amount of time. It spent more time at the slower speed, which gives that speed a greater weight in the average. That explains why the average speed is closer to 
rather than 
.
The strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.
<h3>
</h3><h3>What is the electric field strength?</h3>
The electric field strength is defined as the ratio of electric force to charge.
Given data;
q₁ = 5.4 C
F₁ is the electric force in case1
E is the electric field =?
F₂ is the electric force in case 2
q₂ is the charge 2
The strength of the electric field at that point is;
F₁=Eq₁
E₁=F/q₁
E₁=25.0 N / 5.4 C
E₁=4.587 N/C
The force would this charge experience at that point when the charge is 2.7 C;
F₂=Eq₂
F₂=4.587 N/C × 2.7 C
F₂ = 12.38 N
Hence the strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.
To learn more about the electric field strength, refer to the link;
brainly.com/question/4264413
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Explanation:
Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.
The earths rotation makes the sky "move" and this rotates the view of the stars above.
Answer:
Angle = 0.2520 radians
Explanation:
Complete question:
Sound with frequency 1220Hz leaves a room through a doorway with a width of 1.13m . At what minimum angle relative to the centerline perpendicular to the doorway will someone outside the room hear no sound? Use 344m/s for the speed of sound in air and assume that the source and listener are both far enough from the doorway for Fraunhofer diffraction to apply. You can ignore effects of reflections.
Given Data:
Speed of sound =v= 344 m/sec ;
Width of doorway =d= 1.13m ;
Frequency of sound =f= 1220 Hz ;
Solution:
As we know that
Wvelength = w = v/f = 344/1220 = 0.281967m
Now we also know that
w = dsin(A) where A is the angle
A = arcsin(w/d) =14.44° = 14.44*(3.14/180) = 0.2520 radians
At the angle of 0.252 radians relative to the centreline perpendicular to the doorway a person outside the room will hear no sound under given conditions.
