Question

What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force is applied

Answer 1

Answer:

The friction coefficient's minimum value will be "0.173".

Explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒ $F_{net}=ma$

           $=5\times 1.7$

           $=8.5 \ N$

(b)

For m₃,

⇒ $ma=\mu m_3 g$

Or,

⇒    $\mu=\frac{a}{g}$

          $=\frac{1.7}{9.8}$

          $=0.173$