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Aleonysh [2.5K]
3 years ago
7

An object moves 100m distance in 5 second.find its speed?​

Physics
1 answer:
otez555 [7]3 years ago
7 0

speed =  \frac{distance}{time}  \\  = 100 \div 5 \\  = 20m \: per \: second

<h2>Final Answer: 20m/s</h2>
  • The object moves at the speed of 20m per sec.

<h2>☆彡Hanna</h2>

#CarryOnLearning

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A small metal sphere has a mass of 0.16 g and a charge of -23.0 nC . It is 10 cm directly above an identical sphere with the sam
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Explanation:

A) we know that the magnitude of force

F= \frac{kq_1q_2}{d^2}

F= \frac{9\times10^9\times23\times10^{-9}\times23\times10^{-9}}{0.1^2

= 4.761×10^{-4} N

Also, net force = gravitational force - electrostatic force

B) F_net = F_g - F_e

m×a = m×g - 4.761×10^-4

a = g - 4.761×10^{-4}÷m

a= 9.8 - (4.761×10^{-4} /0.16×10^{-3})

a= 9.8 -2.975625

a= 6.82 m/s

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3 years ago
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A 15 kg cart is pushed on a frictionless surface from rest horizontally by a 30 N force. What is the cart's acceleration?
Rainbow [258]

Answer:

<em>a. The cart's acceleration is 2 m/s^2</em>

<em>b. The cart will travel 100 m</em>

<em>c. The speed is 20 m/s</em>

Explanation:

a. The acceleration of the cart can be calculated using Newton's second law:

F = m.a

Solving for a:

\displaystyle a=\frac{F}{m}

The cart has a mass of m=15 Kg and is applied a net force of F=30 N, thus:

\displaystyle a=\frac{30}{15}

a=2\ m/s^2

b.

Now we use kinematics to find the distance and speed:

\displaystyle x = v_o.t+\frac{at^2}{2}

The cart starts from rest (vo=0). The distance traveled in t=10 seconds is:

\displaystyle x = 0*10+\frac{2*10^2}{2}

x = 100\ m

The cart will travel 100 m

c.

The final speed is calculated by:

v_f=0+2*10=20\ m/s

The speed is 20 m/s

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3 years ago
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4 years ago
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A bullet of mass 0.017 kg traveling horizontally at a high speed of 290 m/s embeds itself in a block of mass 5 kg that is sittin
rodikova [14]

Answer:

(a) vf = 0.98 m/s

(b) K₁ = 714.85 J : Total translational kinetic energy before the collision.

K₂=  2.41 J : Total translational kinetic energy after the collision.

Explanation:

Theory of collisions  

Linear momentum is a vector magnitude (same direction of the velocity) and its magnitude is calculated like this:    

p=m*v  

where  

p:Linear momentum  

m: mass  

v:velocity  

There are 3 cases of collisions : elastic, inelastic and plastic.  

For the three cases the total linear momentum quantity is conserved:  

P₀ = Pf Formula (1)  

P₀ :Initial linear momentum quantity  

Pf : Final linear momentum quantity  

Data

m₁ = 0.017 kg : mass of the bullet

m₂ = 5 kg : mass of the block

v₀₁ =  290 m/s : initial velocity of the bullet

v₀₂ = 0  : initial velocity of the block₂

(a) Speed of the block after the bullet embeds itself in the block

We appy the formula (1):

P₀ = Pf  

m₁*v₀₁ + m₂*v₀₂ = (m₁+ m₂)vf  

vf: final velocity of the block

( 0.017)*( 290) + (5)*(0) = ( 0.017 + 5 )*vf

4.93+ 0 = (  5.017 )*vf

vf = 4.93 / 5.017

vf = 0.98 m/s

b)  Total translational kinetic energy before (K₁) and after the collision(K₂).

K₁ = 1/2(m₁*v₀₁² + m₂*v₀₂²)

K₁ = 1/2(0.017*(290)² + 5*(0)²) = 714.85 J

K₂= 1/2(m₁+ m₂)*vf²

K₂= 1/2(0.017+ 5)*(0.98)²  = 2.41 J

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