(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
A.) the 15th day, because you would the less common multiple is 15 of 3 and 5.
Answer:
f(-1)=6
Step-by-step explanation:
Answer:
x < ( -2b+8)/-a
Step-by-step explanation:
-ax + 2b > 8
Subtract 2b from each side
-ax + 2b-2b >-2b+ 8
-ax > -2b+8
Divide each side by -a, remembering to flip the inequality
-ax /-a < (-2b+8)/ -a
x < ( -2b+8)/-a
Answer: The answer is 9 because the equations represent the same expression but just in different forms.
Step-by-step explanation:
