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Alex Ar [27]
4 years ago
5

Simplify this expression.

Mathematics
2 answers:
Ilia_Sergeevich [38]4 years ago
8 0

<em>Answer:</em>

<em></em>\frac{6w^2 y^4}{x}<em></em>

<em>Step-by-step explanation:</em>

<em></em>\frac{12x^3 y^6 w^5}{2x^4 y^2 w^3}<em></em>

<em></em>= \frac{12w^5 x^3 y^6}{2w^3 x^4 y^2}<em></em>

<em></em>= \frac{12w^2 y^4}{2x}<em></em>

<em></em>= \frac{6w^2 y^4}{x}<em></em>

<em>Hope this helped you!</em>

Margarita [4]4 years ago
7 0

Answer

\frac{ 6   {y}^{4}  {w}^{2} }{{x}}

Step-by-step Explanation

\huge \frac{12 {x}^{3} {y}^{6}   {w}^{5} }{ 2{x}^{4} {y}^{2}   {w}^{3} }  \\  \\  \huge= \frac{6 {x}^{3} {y}^{6}   {w}^{5} }{{x}^{4} {y}^{2}   {w}^{3} }  \\  \\ \huge = 6 {x}^{3 - 4}  {y}^{6 - 2}  {w}^{5 - 3}  \\  \\ \huge= 6 {x}^{ - 1}  {y}^{4}  {w}^{2}  \\  \\ \huge =  \frac{ 6   {y}^{4}  {w}^{2} }{{x}^{1}} \\  \\ \huge =  \frac{ 6   {y}^{4}  {w}^{2} }{{x}}

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Substituting A into B
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Using the quadratic formula:
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Subtracting 7 gives us the base length
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**************************************************************
Double-Check
.5 * 15 * 8 = 60


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