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2 years ago

Log_8(5x+4)=3x-4

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

6 0

The equivalent equation of the logarithmic equation is $5x + 4 = 8^{3x - 4}$

<h3>How to rewrite the equation?</h3>

The logarithmic equation is given as

Log_8(5x+4)=3x-4

Rewrite properly as:

$\log_8(5x+4)=3x-4$

Apply the following law of logarithm

$\log_a(b) = x \to a = b^x$

So, we have:

$5x + 4 = 8^{3x - 4}$

Hence, the equivalent equation of the logarithmic equation is $5x + 4 = 8^{3x - 4}$

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2(x+7) + x=20
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3x+14=20
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3x/3 6/3 Divide Both Sides by 3

x = 2

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What type of angle is angle G?<br><br> A. obtuse<br> B. straight<br> C. acute<br> D. right

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3 years ago

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He buys three cups of hot choclate cause 1.50*3= 4.50
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3 years ago

f(x)=5x reflected over the x axis

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3 years ago

PLEASE HELPP

agasfer [191]

Answer:

The solution to the system of equations be:

$x=3,\:y=-1$

Hece, option B is correct.

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}x-3y=6\\ 2x+2y=4\end{bmatrix}$

Multiply x − 3y = 6 by 2: 2x-6y=12

$\begin{bmatrix}2x-6y=12\\ 2x+2y=4\end{bmatrix}$

$2x+2y=4$

$-$

$\underline{2x-6y=12}$

$8y=-8$

so the system of equations becomes

$\begin{bmatrix}2x-6y=12\\ 8y=-8\end{bmatrix}$

Solve 8y = -8 for y

$8y=-8$

Divide both sides by 8

$\frac{8y}{8}=\frac{-8}{8}$

$y=-1$

$\mathrm{For\:}2x-6y=12\mathrm{\:plug\:in\:}y=-1$

$2x-6\left(-1\right)=12$

$2x+6=12$

subtract 6 from both sides

$2x+6-6=12-6$

$2x=6$

Divide both sides by 2

$\frac{2x}{2}=\frac{6}{2}$

$x=3$

Therefore, the solution to the system of equations be:

$x=3,\:y=-1$

Hence, option B is correct.

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3 years ago

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