A store gives a customer 20% off if $10 or more amount of product is purchased. Otherwise the customer pays the usual price at c
heckout. The amount of product a customer purchases is modeled by a continuous random variable X with density
 
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:
The expected payment by the customer at the checkout is $9. 
Step-by-step explanation:
The amount of the product is given as 

Now the expected payment is given as

Here 0.8 x is used in the second integral because of the discount of 20% i.e. the expected price is 80% of the value such that
![\\EP=\int\limits^{10}_{5} {x \frac{50}{x^3}} \, dx +\int\limits^{\infty}_{10} {0.8x \frac{50}{x^3}} \, dx\\\\EP=\int\limits^{10}_{5} {\frac{50}{x^2}} \, dx +\int\limits^{\infty}_{10} {\frac{40}{x^2}} \, dx\\EP=[\frac{50}{-x}]_5^{10} +[\frac{40}{-x}]_{10}^{\infty} \\EP=[\frac{-50}{10}+\frac{50}{5}] +[\frac{-40}{\infty}+\frac{40}{10}]\\\\EP=-5+10+0+4\\EP=9](https://tex.z-dn.net/?f=%5C%5CEP%3D%5Cint%5Climits%5E%7B10%7D_%7B5%7D%20%7Bx%20%5Cfrac%7B50%7D%7Bx%5E3%7D%7D%20%5C%2C%20dx%20%2B%5Cint%5Climits%5E%7B%5Cinfty%7D_%7B10%7D%20%7B0.8x%20%5Cfrac%7B50%7D%7Bx%5E3%7D%7D%20%5C%2C%20dx%5C%5C%5C%5CEP%3D%5Cint%5Climits%5E%7B10%7D_%7B5%7D%20%7B%5Cfrac%7B50%7D%7Bx%5E2%7D%7D%20%5C%2C%20dx%20%2B%5Cint%5Climits%5E%7B%5Cinfty%7D_%7B10%7D%20%7B%5Cfrac%7B40%7D%7Bx%5E2%7D%7D%20%5C%2C%20dx%5C%5CEP%3D%5B%5Cfrac%7B50%7D%7B-x%7D%5D_5%5E%7B10%7D%20%2B%5B%5Cfrac%7B40%7D%7B-x%7D%5D_%7B10%7D%5E%7B%5Cinfty%7D%20%5C%5CEP%3D%5B%5Cfrac%7B-50%7D%7B10%7D%2B%5Cfrac%7B50%7D%7B5%7D%5D%20%2B%5B%5Cfrac%7B-40%7D%7B%5Cinfty%7D%2B%5Cfrac%7B40%7D%7B10%7D%5D%5C%5C%5C%5CEP%3D-5%2B10%2B0%2B4%5C%5CEP%3D9)
The expected payment by the customer at the checkout is $9. 
 
                                
             
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Answer:
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if x is 8 then 12(8) + 12
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Top left corner probably depends on what device you’re using