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scoundrel [369]

3 years ago

12

Evaluate the indefinite integral. (remember to use absolute values where appropriate. use c for the constant of integration.) dx

hx + q (h ≠ 0

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

:) Well, I dunno about anyone else but this question makes my head spin!

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There are 65 pens in 3 boxes. How many pens are in 12 boxes?

Rainbow [258]

Answer:

260

Step-by-step explanation:

6 0

3 years ago

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Please help picture below

Gekata [30.6K]

A. The sculptor will have to sculpt away 1M on each side.

Explanation: 3 • 1_1/2 • 1_1/2
To get to 2 • 1/2 • 1/2, subtract 1 meter from each side of the rectangular prism and you’ll get that! :)

7 0

3 years ago

I need help show your work

Vlad1618 [11]

If x = 2 than, 6(4x2)=48
-3(8x)= -24
It would equal 24

6 0

3 years ago

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For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

4 0

3 years ago

The midsegment of a trapezoid is always parallel to each base true or false

Deffense [45]

Answer:

True

Step-by-step explanation:

we know that

The <u><em>Trapezoid Mid-segment Theorem</em></u> states that : A line connecting the midpoints of the two legs of a trapezoid is parallel to the bases, and its length is equal to half the sum of lengths of the bases

see the attached figure to better understand the problem

EF is the mid-segment of trapezoid

EF is parallel to AB and is parallel to CD

EF=(AB+CD)/2

so

The mid-segment of a trapezoid is always parallel to each base

therefore

The statement is true

8 0

3 years ago