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fgiga [73]
2 years ago
10

Determine the domain of the function, and then graph it.

Mathematics
1 answer:
Tomtit [17]2 years ago
6 0
First set change the function f(x) to y so
that it would be
y = \sqrt{x + 4} - 1
Then set y = 0
0 = \sqrt{x + 4} - 1
Then solve for x

X = - 3

To graph it, just plot the point (-3,0) on the x-axis
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Which is an equation of an asymptote of the hyperbola?
Vikentia [17]
Follow the method of rise over run and a is your answer
3 0
3 years ago
I NEED THE ANSWER ITS DUE SOON !!! Points will be rewarded
DENIUS [597]

Answer:

Jaden added instead of subtracting 23 and 5

Step-by-step explanation:

3 0
2 years ago
Correct answers only please!
Naily [24]

Answer:  

1st Question

A. 85

2nd Question  

B. 71

Step-by-step explanation:

1st Question

{90 + 94 + 96 + 90} = 370/4 = 92.5

{95 + 99}                  = 194/2 = 97

{87 + 75 + 82 + 85} = 329/4 = 82.25

{71}                =  71/1               = 71

.20(92.5) +.25(97) +.30(82.25) +.25(71) = 85.175  Rounded-up = 85

___________________________________________________

2nd Question  

.10(95) +.20(80) +.50(67) +.20(60) = 71

7 0
3 years ago
J= -8c^2 - 4cd - d^2 k= -3c^2 +7cd - 3d^2 j+k =
irina [24]
J=-8c²-4cd-d²
k=-3c²+7cd-3d²
j+k=
-8c²-4cd-d²-3c²+7cd-3d²
-11c²-4d²+3cd
6 0
3 years ago
Does the equation x^2+y=144 define y as a function of x?
11Alexandr11 [23.1K]

The given equation is

x^2 + y = 144

First we solve for y, and for that, we have to islolate y, that is

y= 144-x^2

And it pass the vertical line test. So here y is a function of x .

So we can define the given equation as y as a function of x .

8 0
2 years ago
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