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1 year ago

11

HbhhhhvbvbbhHzhzhhshhjzjzbsjzjsjjsujenwja

1 answer:

sineoko [7]1 year ago

6 0

Answer:

hgfhdgsgzfzsgfzgzfffdfdsfdfgfghgf

Step-by-step explanation:

...

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The graph of f(x) = 6(0.25)x and its reflection across the y-axis, g(x), are shown.

jeka57 [31]

<u>Answer-</u>

The domain of g(x) is all real numbers.

<u>Solution-</u>

The given function is,

$f(x)=6(0.25)^x$

The reflection across y-axis of a point (x, y) will be (-x, y)

So, the reflection of the given function across y-axis will be,

$g(x)=6(0.25)^{-x}$

It is an exponential function. The domain of exponential functions is all real numbers and the range is all real numbers greater than zero.

Therefore, first option is correct.

6 0

2 years ago

Read 2 more answers

Find the arc length intercepted by a central angle of radians in a circle whose radius is 18.4 inches. 13.8π 15.2π 24.5π

Margarita [4]

If the measure of the given central angle is $\theta$ rad, then the length of the subtended arc is $\ell$ satisfying

$\dfrac{\ell}{2\pi(18.4\,\mathrm{in})}=\dfrac{\theta\,\mathrm{rad}}{2\pi\,\mathrm{rad}}\implies\ell=36.8\pi\theta\,\mathrm{in}$

It's not clear from the question what the value of $\theta$ is...

7 0

2 years ago

Read 2 more answers

The front wall of the storage shed is in the shape of a trapezoid.

KonstantinChe [14]

Answer:

66 square feet

Step-by-step explanation:

please review the attachment for a detailed explanation

7 0

2 years ago

The longer leg of a 30°- 60°- 90° triangle is 4 3 cm. Which is the length of the hypotenuse?

liberstina [14]

i think its 25 because of the Pythagorean theorem. 4^2 + 3^2= 16 + 9 =25

When you find the square root of 25 its 5

6 0

2 years ago

I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?

Valentin [98]

Given:

In a number, adding $1\dfrac{3}{4}$ , then multiplying the result by $2\dfrac{2}{11}$ we get 8.

To find:

The unknown number.

Solution:

Let the unknown number be x.

According to the question,

$(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8$

$(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8$

$(x+\dfrac{4+3}{4})\times \dfrac{22+2}{11}=8$

$(x+\dfrac{7}{4})\times \dfrac{24}{11}=8$

Multiply both sides by $\dfrac{11}{24}$ .

$x+\dfrac{7}{4}=8\times \dfrac{11}{24}$

$x+\dfrac{7}{4}=\dfrac{11}{3}$

Subtract $\dfrac{7}{4}$ from both sides.

$x=\dfrac{11}{3}-\dfrac{7}{4}$

$x=\dfrac{44-21}{12}$

$x=\dfrac{23}{12}$

$x=1\dfrac{11}{12}$

Therefore, the required number is $1\dfrac{11}{12}$ .

3 0

2 years ago