Question

A skateboarder has an initial velocity of 3 m/s West and comes to a stop in 2 seconds. What is the skateboarder's

Answer 1

Answer:

-1.5 m/s/s

Explanation:

What you know:

v1= 3 m/s

t (Time)= 2 seconds

v2= 0 m/s

So you plug those variables into the equation v2=v1+at and solve for a.

0= 3 +2a

-1.5=a

Answer 2

Answer:

FV- 0 m/s

IV- 3 m/s

t- 2 sec

A= FV-IV/t

A= 0-3/2

a= -1.5 m/s²

Explanation:

FV- Final Velocity -> m/s

IV- Initial Velocity -> m/s

A- Acceleration -> m/s²

t- time -> seconds