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3 years ago

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An art club sells 42 large candles and 56 small candle price of large candle is $10 the cost is $x a small candles cost $5 and c

ost is $y use the distributive property to right and simplify an expression for the profit

1 answer:

balandron [24]3 years ago

4 0

Answer:

Profit = $(700 - 42x - 56y)

Step-by-step explanation:

For large candles, the selling price is $10 and its making cost is $x.

So, by selling a large candle the profit is $(10 - x)

Again for small candles, the selling price is $5 and its making cost is $y.

So, by selling a small candle the profit is $(5 - y)

Therefore, in a sell of 42 large candles and 56 small candles the total profit will be, P = 42 (10 - x) + 56 (5 - y)

⇒ P = 420 - 42x + 280 - 56y {Applying distributive property}

⇒ P = $(700 - 42x - 56y) (Answer)

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Estimate 22,752 divided by 16

horrorfan [7]

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Other Divisions Math homework are

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3 years ago

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20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha

zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 300, p = 0.2$

So

$\mu = E(X) = np = 300*0.2 = 60$

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What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is $P(X \leq 51 + 0.5) = P(X \leq 51.5)$ , which is the pvalue of Z when X = 51.5 So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{51.5 - 60}{6.9282}$

$Z = -1.23$

$Z = -1.23$ has a pvalue of 0.1093.

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