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Andru [333]
3 years ago
14

10 people want to share 84 pounds of candy so that each person gets the same amount. Exactly how many pounds of candy should eac

h person get?
Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0
I think it’s 8.4 pounds
kotegsom [21]3 years ago
3 0
8.4 pounds each is what they should do

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My question is 4% of what is 56?
Scrat [10]

<span>4% is the same as 0.04 </span>

<span>so 0.04 x n = 56 where "n" is some number </span>

<span>0.04n = 56 Divide both sides by 0.04 </span>

<span>n = 1400</span>
4 0
3 years ago
There are 3 feet in each yard. Complete the table to show the number of feet in 1, 2, 3, and 4 yards.
MariettaO [177]

Answer:

1 yard = 3 feet

2 yard = 6 feet

3 yard = 9 feet

4 yard = 12 feet

7 0
3 years ago
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Solve -7x^2+x+9=-6x quadratic formula
myrzilka [38]

Answer:

-7x^2+x+9=-6x

-7x^2+x+9+6x=-6x+6x

-7x^2+7x+9=0

quadratic\: formula

x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}

\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}

x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}

\frac{-7+\sqrt{301}}{2\left(-7\right)}

=\frac{-7+\sqrt{301}}{-2\cdot \:7}

=\frac{-7+\sqrt{301}}{-14}

\frac{-7-\sqrt{301}}{2\left(-7\right)}

=\frac{-7-\sqrt{301}}{-2\cdot \:7}

=\frac{-7-\sqrt{301}}{-14}

answer=\frac{7+\sqrt{301}}{14}

OAmalOHopeO

7 0
3 years ago
Find the equivalent fraction for 10/20
dezoksy [38]
\frac{10}{20} =  \frac{ \frac{10}{10} }{ \frac{20}{10} } =  \frac{1}{2}
6 0
3 years ago
(a) Let R = {(a,b): a² + 3b &lt;= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
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