All categories

3 years ago

What unit rate describes 100

1 answer:

6 0

And you know right this girl has how many years of the first type of quantity of correspond to one unit of the second type of quantity

You might be interested in

a delivry truck is transporiting boxes of two sizes large and small the combined weight of a large box and a small box is 65 pou

Semenov [28]

Answer: S = 20 lbs L = 45 lbs. Both answer have been rounded from below

Step-by-step explanation:

L+S = 65 lbs

55L + 65S = 3774 lbs

55L+55S = (65)(55) = 3,575 lbs

10S = 199 lbs

S = 19.99 (round to 20)

L + S = 65

L + 19.99 = 65

L = 45.01 (round to 45)

3 0

3 years ago

What’s the area of this figure?

11Alexandr11 [23.1K]

Answer:

13 sq cm.

Step-by-step explanation:

To find the area of this irregular figure, we will need to find the areas of a rectangle and triangle within this figure.

To find the area of the rectangle, we can simply do:

1 × 4= 4 sq cm.

Now, this is where it gets a little trickier. To find the area of the triangle, we will first need to determine the base and height.

We can see from the diagram that to find the base, we need to subtract:

7-4= 3 cm. This is the base of ONLY the triangle.

To find the height, we will need to do:

5+1= 6 cm. This is the total height of the entirety of the triangle.

We can now use the Triangle Area formula: $\frac{1}{2}$ (bh), to calculate the area of the triangle.

$\frac{1}{2}$ (6*3)= 9 sq cm.

Finally, add the areas of the rectangle and triangle together, giving you:

9+4= 13 sq cm.

3 0

3 years ago

a reduced fat cookie contains 11g of fat per serving. in order for food to be termed 'reduced fat', it must have at least 20% le

Svetllana [295]

Personally, I did this in a kinda weird way but I think that it should be correct

-How I figured the answer out-

I took 11g and wrote 80% next to it, because after all it has 80% less fat than the regular cookie.

Then, I scaled it down to 10% by dividing by 8, which got me

1.375g = 10%

And finally, I multiplied by 10 to now have 100% (meaning, a regular serving size cookie) and be left with the result: 13.75g

-The answer-

13.75g (don't forget to write the units)

Have a great day :)

6 0

3 years ago

PLEASE help I will mark you BRAINLIEST!!! <br>

koban [17]

Answer:

Use shell method

And chose the cross section perpendicular to the x-axis

8 0

3 years ago

Find the absolute maximum and minimum values of f on the set D. f(x,y)=2x^3+y^4, D={(x,y) | x^2+y^2<=1}.

castortr0y [4]

Answer:

absolute maximum is f(1, 0) = 2 and the absolute minimum is f(−1, 0) = −2.

Step-by-step explanation:

We compute,

$f_x = 6x^2, f_y=4y^3$

Hence, $f_x = f_y = 0$ if and only if (x,y) = (0,0)

This is unique critical point of D. The boundary equation is given by

$x^2+y^2=1$

Hence, the top half of the boundary is,

$$ T = \{ x, \sqrt{1-x^2} : -1 \leq x \leq 1\}$

On T we have, $f(x, \sqrt{1-x^2} = 2x^3 +(1-x^2)^2 = x^4 +2x^3-2x^2+1 \text{ for}\ -1 \leq x \leq 1$

We compute

$\frac{d}{dx}(f(x, \sqrt{1-x^2}))= 4x^3+6x^2-4x = 2x(2x^2+3x-2)=2x(2x-1)(x+2)=0$

0 if and only if x=0, x= 1/2 or x = -2.

We disregard $x = -2 \notin [-1,1]$

Hence, the critical points on T are (0,1) and $(\frac{1}{2}, \sqrt{1-(\frac{1}{2})^2}=\frac{\sqrt3}{2})$

On the bottom half, B, we have

$f(x, \sqrt{1-x^2})= f(x,-\sqrt{1-x^2})$

Therefore, the critical points on B are (0,-1) and $$( 1/2, -\sqrt3/2)$

It remains to evaluate f(x, y) at the points $(0,0), (0 \pm1), (1/2, \pm \sqrt3/2) \text{ and}\ (\pm1, 0)$ .

We should consider latter two points, $(\pm1,0)$ , since they are the boundary points for the T and also B. We compute $f(0,0)=0, \ \f(0 \pm1)=1, \ \ f(0, \pm \sqrt3/2)=9/16, \ \ f(1,0 )= 2 \text{ and}\ \ f(-1,0)= -2$

We conclude that the absolute maximum = f(1, 0) = 2

And the absolute minimum = f(−1, 0) = −2.

6 0

3 years ago