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Alex777 [14]
3 years ago
7

The point P(x, y) is on the terminal ray of angle theta. If theta is between pi and 3pi/2 radians and csc theta equals -5/2 what

are the coordinates of P(x, y)?
Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

Answer:

(-4.58, -2)

Step-by-step explanation:

\theta $ is in between \pi$ and $\frac{3\pi}{2}$ radians \\Therefore, \theta$ is in Quadrant III\\If \csc \theta = -\dfrac{5}{2}$ and cosec \theta = \dfrac{Hypotenuse}{Opposite} \\ $Therefore:\\Hypotenuse = 5\\Opposite $=-2

Using Pythagoras Theorem

5^2=(-2)^2+ x^2\\25=4+x^2\\x^2=21\\x=\sqrt{21} \approx 4.58

Since the angle is in the third Quadrant, Adjacent = -4.58.

Therefore, the coordinates of P(x,y) is (-4.58, -2)

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Here you would use right triangle trig (SOH CAH TOA)
So first draw a right triangle. Imagine youre standing at the angle opposite the right angle which is the one on the ground.This angle is the 41°. Now Imagine the balloon is as the angle above the right triangle. Well since the balloon is 1503 m from his location this would be the hypotenuse. SInce we are trying to find the height (x) we would use sine since
sine = opposite/hypotenuse . Now lets solve make sure calculator is in degree mode:

sin41 = x/1503      multiply both sides by 1503 to cancel it out
1503sin41 = x        plug into calculator
x = 986.057 ft
The balloon is 986.057 feet above the ground.


6 0
3 years ago
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