Answer:
26 units
Step-by-step explanation:
Due to:
in the rect line, left to zero = 13 (absolute value)
in the rect line, right to zero = 13 (absolute value)
So the sum of each absolute value is the distance.
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Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
6108795
Step-by-step explanation:
To obtain the number of ways the committee can be selected :
4 teachers from the 12 teachers available and 3 students from the 43 students available
Using combinatorics :
12C4 * 43C3
recall :
nCr = n! ÷ (n - r)!r!
Using calculator :
12C4 = 495
43C3 = 12341
12C4 * 43C3
495 * 12341
= 6108795