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3 years ago

Please answer me QICK. Can the square root also be a decimal number?

Mathematics

2 answers:

Sladkaya [172]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

forsale [732]3 years ago

3 0

Yes it can also be a decimal number..

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Write 4 numbers that round to 700,000 when rounded to the nearest hundred thousand

enot [183]

Well off the top of my head, (700,001),(700,002),(700,003), and (700,004) are 4 numbers that round to 700,00 when rounded to the nearest hundred thousand. But if you're looking for something a little more unique, then any number from 650,000 to 749,999 would round to to 700,000 when rounded to the nearest hundred thousand. I hope this helps!

4 0

3 years ago

How many equivalence relations are there on the set 1, 2, 3]?

Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0

3 years ago

9. Whats is the equivalent fraction for 0.625

Tatiana [17]

Answer:

5/8

Step-by-step explanation:

You need to convert to a simplified fraction by placing the numbers to the right of the decimal over 1000. Then reduce the fraction.

6 0

2 years ago

Read 2 more answers

The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,

Stella [2.4K]

Answer:

$P_4 = 7604.08$

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

$P_1 = P_0 + 0.04P_0$

Where $P_0$ is the initial population and $P_n$ is the population in year n

In year 2

$P_2 = P_1 + 0.04P_1$

It can also be written as:

$P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)$

Taking out common factor $P_0$

$P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)$

Taking out common factor (1 + 0.04)

$P_2 = (1 + 0.04) (P_0 + 0.04P_0)$

Taking out again common factor $P_0$

$P_2 = (1 + 0.04) (1 + 0.04) P_0$

Simplifying

$P_2 = P_0 (1 + 0.04) ^ 2$

$P_n = P_0 (1 + 0.04) ^ n$

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

$P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08$

3 0

3 years ago

A lawn-mowing company is trying to grow its business. It had 26 clients when they started its business and wants to increase by

Likurg_2 [28]

Answer:

B. f(x) = 3x + 26;26≤ y ≤ 35

Step-by-step explanation:

This would be a linear equation in the form

y= mx+b

where b is the initial value (or 26 clients)

m is the slope, or the amount they want to increase by each week

y = 3x+26

Let x =0

y = 26 or what we start with

Let x =3, or be week 4 (we started with x= 0)

y = 3*3 +26

y =9+26

y= 35

3 0

3 years ago

Read 2 more answers