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Artyom0805 [142]
3 years ago
13

163,160,157,... find the 42nd term

Mathematics
1 answer:
UNO [17]3 years ago
6 0

Answer:

It's 40

Step-by-step explanation:

Arithmetic Sequence.

Common Difference:

160−163=−3

157−160=−3

d=−3

Explicit Formula:

an=a1+(n−1)d

​

a42​=163+(41)(−3)

a42 = 40

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The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
vagabundo [1.1K]

Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

8 0
3 years ago
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The nth term of a sequence is 3n + 2
gavmur [86]

Answer:

see explanation

Step-by-step explanation:

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a_{3} = (3 × 3) + 2 = 9 + 2 = 11

------------------------------------------------------------------

substitute n = 10 into the n th term rule

a_{10} = (3 × 10) + 2 = 30 + 2 = 32

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6(2.90) + 6p = 33.60

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    6p = 16.20
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