<u>Answer:</u>
<u>For a:</u> The molarity of solution is 0.005 M.
<u>For b:</u> The molarity of solution is 0.5 M.
<u>For c:</u> The molarity of solution is 9.92 M.
<u>For d:</u> The molarity of solution is 0.0011 M.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
.....(1)
Mass of cholestrol = 0.195 g
Molar mass of cholestrol = 386.65 g/mol
Volume of solution = 0.100 L
Putting values in equation 1, we get:
Hence, the molarity of solution is 0.005 M.
Mass of ammonia = 4.25 g
Molar mass of ammonia = 17 g/mol
Volume of solution = 0.500 L
Putting values in equation 1, we get:
Hence, the molarity of solution is 0.5 M.
Mass of isopropyl alcohol = 1.49 kg = 1490 g (Conversion factor: 1 kg = 1000 g)
Molar mass of isopropyl alcohol = 60.1 g/mol
Volume of solution = 2.5 L
Putting values in equation 1, we get:
Hence, the molarity of solution is 9.92 M.
Mass of iodine = 0.029 g
Molar mass of iodine = 253.8 g/mol
Volume of solution = 0.100 L
Putting values in equation 1, we get:
Hence, the molarity of solution is 0.0011 M.