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ruslelena [56]
3 years ago
13

Do matter take up space?

Chemistry
2 answers:
elena55 [62]3 years ago
8 0
Yes, i think that matter does take up space. Matter is everything that has mass and takes up space.
Lubov Fominskaja [6]3 years ago
4 0

Matter is anything that takes up space and has mass. Taking up space means that an object has a measurable volume. Mass indicates how much force is required to move the object. Variations of matter include classical matter and dark matter.

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Which statement best describes the relationship between the frequency and energy of light?
Yuki888 [10]

Answer:

i think C the higher the frequency the lower the energy of light.

4 0
2 years ago
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What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h2o at 20°c.)?
Svetllana [295]
The correct answer is 68 g
hope this helps!!
8 0
3 years ago
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5. What is the pH of an aqueous solution of the strong acid, Perchloric Acid (HClO4), with a concentration of 0.007 M?
bogdanovich [222]
Answer:

The pH is approximately: 2.1549

Explanation:

pH = - log(0.007)
8 0
3 years ago
The chart shows the voltage of four electric currents.
masha68 [24]

Answer: The correct option is Current W flows at a higher rate than Current Z.

Explanation: To answer this question, we will require Ohm's law.

Ohm's Law states that the current flowing through a conductor across two points is directly proportional to the voltage difference across that two points.

Mathematically,

V=IR

where, V = voltage

I = Current

R = resistance

For the given question, assuming that the resistance is constant. So, the current is directly proportional to the voltage.

V\propto I

Hence, as the current W is greater of all the given currents so, it will flow at a higher rate.

Therefore, the correct answer is Current W flows at a higher rate than Current Z.

7 0
3 years ago
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Calculate the radius of tantalum (Ta) atom, given that Ta has a BCC crystal structure, a density of 16.6 g/cm, and an atomic wei
Ivahew [28]

Answer:

The radius of tantalum (Ta) atom is R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm

Explanation:

From the Body-centered cubic (BBC) crystal structure we know that a unit cell length <em>a </em>and atomic radius <em>R </em>are related through

a=\frac{4R}{\sqrt{3} }

So the volume of the unit cell V_{c} is

V_{c}= a^3=(\frac{4R}{\sqrt{3} } )^3=\frac{64\sqrt{3}R^3}{9}

We can compute the theoretical density ρ through the following relationship

\rho=\frac{nA}{V_{c}N_{a}}

where

n = number of atoms associated with each unit cell

A = atomic weight

V_{c} = volume of the unit cell

N_{a} =  Avogadro’s number (6.023 \times 10^{23} atoms/mol)

From the information given:

A = 180.9 g/mol

ρ = 16.6 g/cm^3

Since the crystal structure is BCC, n, the number of atoms per unit cell, is 2.

We can use the theoretical density ρ to find the radio <em>R</em> as follows:

\rho=\frac{nA}{V_{c}N_{a}}\\\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}

Solving for <em>R</em>

\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}\\\frac{64\sqrt{3}R^3}{9}=\frac{nA}{\rho N_{a}}\\R^3=\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}} \\R=\sqrt[3]{\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}

Substitution for the various parameters into above equation yields

R=\sqrt[3]{\frac{2\cdot 180.9}{16.6\cdot 6.023 \times 10^{23}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}\\R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm

7 0
3 years ago
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