Answer:
(5.4582 ; 6.8618)
Step-by-step explanation:
Given the data:
6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5
Sample mean, xbar = Σx / n
n = sample size = 50
ΣX = 308
xbar = 308 / 50 = 6.16
Using a Calculator :
The sample standard deviation, s = 2.469
Confidence interval = xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Tcritical at 95% ; df = 50 - 1 = 49
Tcritical = 2.010
Hence,
Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018
Lower boundary : (6.16 - 0.7018) = 5.4582
Upper boundary : (6.16 + 0.7018) = 6.8618
(5.4582 ; 6.8618)
Answer:
5. D (4,6)
6. B (7.8)
Step-by-step explanation:
5. Add the two X coordinates (6+2) and divide that by 2 (8/2=4), do the same for the two Y coordinates (4+8=12, 12/2=6)
6. Use the distance formula 
Input the coordinates 
Answer:
Yes
Step-by-step explanation:
Will you help me please
50 ounces would be bigger
2x + 7 = 3
2x = 3 - 7
2x = -5
x = -5/2
