Using the normal distribution, it is found that 495 readings fall within 5.15cm of the mean value.
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- Mean of 5m, hence
. - Standard deviation of 2 cm, hence
To find the proportion of readings that fall within 5.15cm of the mean value, first we need to find the following z-score:
The proportion is P(|z| < 2.575), which is the p-value of z = 2.575 subtracted by the p-value of z = -2.575.
Looking at the z-table, z = -2.575 has a p-value of 0.005, and z = 2.575 has a p-value of 0.995.
0.995 - 0.05 = 0.99
Out of 500 measurements:
(0.99)500 = 495
495 readings fall within 5.15cm of the mean value.
A similar problem is given at brainly.com/question/24663213
Answer:
Step-by-step explanation:
A. S=strawberry, C=chocolate
S+C=14 equation 1
2s+3c=30 equation 2
B. -2(s+c)=-2(14) multiply equation 1 by -2 to use elimination method
-2s+-2c=-28 modified Equation 1
2s+ 3c=30. Equation 2
C=2 add above two equations.
solve for s
s+c=14
s+2=14
s=12
Used elimination method since it was easier to add the two equations.
check answer by inputting s,c values in either equation.
2s+3c=30
2(12)+3(2)=30
24+6=30
30=30
I need to see the equations to answer the question
The graph which shows the velocity of the particle at any time is attached below.
<h3>How to depict the graph?</h3>
The graph is the rate of change of position of an object with respect to time. Velocity is the speed of an object moving in a definite direction.
Velocity is a vector quantity as it has both magnitude and direction. The velocity of a particle is modeled by the function. It is observed that the given velocity function is a cubic function. The attached graph shows the velocity of the particle at any time.
Learn more about graph on:
brainly.com/question/19040584
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