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stich3 [128]
3 years ago
6

What are the solutions of 3d-<-10or 2d+7>9?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
3 0

3d < -10\ \vee\ 2d+7 > 9\\\\(1)\qquad3d < -10\ \ \ \ |:3\\.\qquad \qquad d < -\dfrac{10}{3}\\\\(2)\qquad2d+7 > 9\ \ \ \ |-7\\.\qquad\qquad2d > 2\ \ \ \ |:2\\.\qquad\qquad d > 1\\\\Answer:\ d < -\dfrac{10}{3}\ \vee\ d > 1\to d\in\left(-\infty,\ -\dfrac{10}{3}\right)\ \cup\ (1,\ \infty)

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Answer:

9+- 1.7

Step-by-step explanation:

Kahn

8 0
2 years ago
Michelle has a jar of quarters and dimes totalling to 3.10 if there are sixteen coins in the jar how many more quarters are ther
Sav [38]
Q + d = 16....q = 16 - d
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0.25(16 - d) + 0.10d = 3.10
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-0.25d + 0.10d = 3.10 - 4
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5 0
3 years ago
Solve the triangle.<br><br> a = 10, b = 23, C = 95°
gayaneshka [121]
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<span>c² = 100 + 529 - (460 * -.08715) </span>
<span>c² = 629 - (-40.1) </span>
<span>c² = 669.1 </span>
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<span>(Sin C) / C = (Sin A) / A </span>
<span>(Sin 95) / 25.87 = SinA / 10, Remember 0 < A < 85 </span>
<span>(10 * Sin95) / 25.87 = Sin A </span>
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<span>A = 22.65º </span>

<span>B = 180 - A - C </span>
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<span>B = 62.35º </span>

<span>I hope this helps. Have a good day.</span>
3 0
3 years ago
How do I solve this problem using the substitution method?
Ira Lisetskai [31]
<span>(y=mx+b) or (ax+by=c)  hope this helped

</span>
8 0
3 years ago
2x+y=5<br> -x+2y=4 <br><br> How do you solve this
d1i1m1o1n [39]
The answer to your problem is
x=5/2
y=5

x=-4
y=2
7 0
3 years ago
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