The coefficient of the variable will be the horizontal asymptote . Hence the horizontal asymptote will be 3
<h3>How to calculate the y-intercept and horizontal asympototes</h3>
Given the function g(x) = 3x + 4
The y-intercept is the point where x = 0
g(0) = 3(0) + 4
g(0) = 0 + 4
g(0) = 4
Hence the y-intercept is at (0, 4)
For the horizontal asymptote of g(x) = 3x + 4
The coefficiet of the variable will be the horizontal asymptote . Hence the horizontal asymptote will be 3
Learn more on asymptotes here: brainly.com/question/4138300
Center of circle = (5,-6)
equation = (x-5)^2+ (x+6)^2 = 3^2
The least common denominator of 5/12 and -9/16
The answer is 48.
Now, we have to change the numerators also to make this a equal fraction to the first ones we had.
5*4 = 20
12*4 = 48
20/48
-9*3 = -27
16*3 = 48
-27/48
We will first add 1/2 to both sides to get 3x = 9
We then divide both sides by 3 to get
x =3 (D)
First off, your chances of red are not really 50-50. You are overlooking the 0 slot or the 00 slot which are green. So, chances of red are 18 in 37 (0 slot) or 38 (0 and 00 slots). With a betting machine, the odds does not change no trouble what has occurred before. Think through the simplest circumstance, a coin toss. If I toss heads 10 times one after the other, the chances of tails about to happen on the next toss are still on a 50-50. A betting machine has no ability, no plan, and no past.
Chances (0 slot) that you success on red are 18 out of 37 (18 red slots), but likelihoods of losing are 19 out of 37 (18 black plus 0). For the wheel with both a 0 and 0-0 slot, the odds are poorer. You chances of red are 18 out of 38 (18 red slots win), and down are 20 out of 38 (18 black plus 0 and 00). It does not really matter on how long you play there, the probabilities would always continue the same on every spin. The lengthier you play, the more thoroughly you will tie the chances with a total net loss of that portion of a percent in accord of the house. 18 winning red slots and either 19 or 20 losing slots.
