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Volgvan
3 years ago
6

Which of the following equations have no solution? Check all that apply.

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0
6x+1 = 3(2x-4)
-4(x+3) = 4(x-1)
Karolina [17]3 years ago
8 0
6x+1=3(2x-4) is no solution.
Reason:
6x+1=6x-12
-6x -6x
1≠-12

The answer is just the first option. Every equation has a solution.
The third option is an infinite solution. The first option is the only one with no solution.
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Help please! very confused
Lera25 [3.4K]

Answer:

???ummm no details

Step-by-step explanation:

5 0
3 years ago
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What is the solution to the system of equations? 6x-2y=10 and y=3x-5
notsponge [240]

Answer:

(2,1)

Step-by-step explanation:

X=2 and y=1

7 0
3 years ago
Q=(c+d)/2 solve for d
UkoKoshka [18]
Q=(c+d)/2
Multiply both sides by 2 to get rid of the 2
2×q=(c+d)
Subtract c from both sides to get rid of the c
2×q-c=d
Flip the equation around
d=2×q-c
8 0
3 years ago
5x²+4x+3=0 solve for x​
juin [17]

Answer:

{ \underline{ \sf{x  \: is  \:  \: \{ \frac{ - 5 + i \sqrt{35} }{10} \} } \:  \: and \:  \:  \{ \frac{ - 5  - i \sqrt{35} }{10}  \}} }

Step-by-step explanation:

5 {x}^{2}  + 4x + 3 = 0

from quadratic formular:

{ \sf{x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }}

general equation:

{ax}^{2}  +  bx + c = 0

a is 5, b is 4 and c is 3:

substitute in formular:

{ \sf{x =  \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 5 \times 3) } }{(2 \times 5)} }} \\  \\ { \sf{x =  \frac{ - 5± \sqrt{ - 35} }{10} }}

but from complexes, <em>i</em><em>²</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em>

{ \sf{x =  \frac{ - 5± \sqrt{35 {i}^{2} } }{10} }} \\  \\  = { \sf{x =   \frac{ - 5±i \sqrt{35} }{10} }}

6 0
3 years ago
I need more help please!!!!!!!!
inysia [295]

Answer:

1. t<45° 2. d≥200

Step-by-step explanation:

t is less than 45°

it said no less than meaning you can spend 200 or more to get the discount so that means d≥200

6 0
3 years ago
Read 2 more answers
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