For the answer to the question above, I'll use one-time computing.
<span>Interest = Principal * rate * (loan duration/time unit) </span>
<span>= $1500 * 4.9% * (125 days/365 days) </span>
<span>Normally, a bank or accountant WOULD NOT use your method of rounding in the middle of the calculation but rather would round the final result. This is the normal way to handle all such mathematical processes. However, for your question, </span>
<span>= $1500 * 4.9% * 0.34 </span>
<span>= $24.99 </span>
<span>If you don't do the rounding in the middle of the calculation, the answer is $25.17.
I hope this helps.</span>
The correct answer to your question is k=5 .
Decay every two years over a period of t years:
Fourth option: f(t)=(0.75)^(t/2)
decay 2 times a year over a period of t years:
Second option: f(t)=(0.9306)^(2t)
Sixth option: f(t)=(0.8660)^(2t)
decay once per year over a period of t years:
First option: f(t)=(0.9306)^t
Third option: f(t)=(0.8660)^t
To do this, set this up like a fraction and solve for x
7/9 = x/450
(7/9) x 450 = x
x= 350 students
This is like finding an equivalent fraction for 7/9 :) hope this helps! <span />
will be 34/12 i did the math for you don’t worry
