Andrew can reach a maximum of 
high up the wall.
The right-angled triangle formed can be solved using the 
ratio. that is
where 
is the distance from the foot of the wall to the tip of the ladder where it rests on the wall. Substituting, and solving for , we get
Since Andrew can reach an extra 
above the point where the ladder rests against the wall, the maximum height Andrew can paint is
Another solved word problem on trigonometry can be found here: brainly.com/question/12146092
<h3>
Answer: 24 yards, choice D</h3>
There are 4 sides to this figure (trapezoid). The left slanted side and the right most vertical side, combined with the top and bottom horizontal sides, will get us the perimeter.
left slanted side = 5 yards
right most vertical side = 4 yards (see note below)
bottom side = 9 yards
top side = 6 yards
Add up the four sides mentioned: 5+4+9+6 = 9+15 = 24
note: the rectangle has opposite sides that are the same length. While the right most side isn't labeled, it is the same length as the left side of the rectangle, so both are 4 yards long.
Another thing I should probably mention is that we do not add in the interior 4 yard side. The perimeter is only the outer or exterior sides we care about. Think of it like we're trying to fence around some property lot and we don't want to subdivide the property up. Finding the perimeter will help us find the amount of fencing needed to surround the property.
Answer:
8
Step-by-step explanation:
Reduce the fraction to 1/2 then multiply it by 8 which is 8:) this this helps! Plzz mark brainliest
4x+4(3)+4(2)=y
4x+20=y
X equals the amount it cost for each ticket which is unknown. Y equals the total cost. Because the amount of the food is provided, it can be calculated unlike the tickets which is just left at 4x. The work for the snacks are upwards. Its mostly substitution.
Ok so for every 1 centimeter you get 10 millimeters. Meaning that if you multiply 20 * 10 you get 200 millimeters and if you multiply 10 * 10 you get 100. Now you subtract 200-100 and you get 100 millimeters.
