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3 years ago

Are there 123 tens in 1235.3

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

7 0

yes

Step-by-step explanation:

there are 100 tens in 1 thousand

20 tens in 200

and 3 tens in 30

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PLEASE HELP ME IT'S DUE LIKE RN!!!

ivanzaharov [21]

Answer:

You can plug in the pair into the equation

Step-by-step explanation:

You take the ordered pair and plug it into the equation. If it matches, that is your solution

For example: y=2x+1 . Pair: (1,3)

Plug 3 for y and 1 for x. 3=2(1)+1 is 3

5 0

2 years ago

Read 2 more answers

Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (N

prisoha [69]

Answer:

The solution to this system of equations is:

B = 28
T = 19

Step-by-step explanation:

We are given that Jill has 47 bugs and counts a total 320 legs.

We can concur that by adding the total number of butterflies and the total number of tarantulas, we will get 47 bugs.

$\text{tarantulas + butterflies} = 47$

We are also told that T is tarantulas and B is butterflies.

$T + B = 47$

Then, we also know that butterflies have 6 legs and tarantulas have 8 legs. So, for every tarantula, we get a multiple of 8 and for butterflies, we get a multiple of 6. This gives us a new equation:

$6B + 8T = 320$

Now, we can set up a system of equation.

$\displaystyle \left \{ {{B + T = 47} \atop {6B + 8T = 320}} \right.$

Using the first equation, we can solve for B.

$\displaystyle B + T = 47\\\\B + T - T = 47 - T\\\\B = 47 - T$

Then, we can substitute this value of B into the second equation and solve for T.

$\displaystyle 6(47-T)+8T=320\\\\282 - 6T + 8T = 320\\\\282 + 2T = 320\\\\2T + 282 = 320\\\\2T + 282 - 282 = 320 -282\\\\2T = 38\\\\\frac{2T}{2}=\frac{38}{2}\\\\T = 19$

Finally, we can substitute this value of T into the first equation to solve for B.

$B + 19 = 47\\\\B + 19 - 19 = 47 - 19\\\\B = 28$

Therefore, the solution to this system of equations is:

B = 28
T = 19

7 0

2 years ago

(2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i)

anygoal [31]

Answer:

Step-by-step explanation:

Given the expression (2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i), we are to take the product of all the complex values. We must note that i² = -1.

Rearranging the expression [(3 - i)(3 + i)] [(2 + i)(1 - i)](1 + 2i)

On expansion

(3 - i)(3 + i)

= 9+3i-3i-i²

= 9-(-1)

= 9+1

(3 - i)(3 + i) = 10

For the expression (2 + i)(1 - i), we have;

(2 + i)(1 - i)

= 2-2i+i-i²

= 2-i+1

= 3-i

Multiplying 3-i with the last expression (1 + 2i)

(2 + i)(1 - i)(1 + 2i)

= (3-i)(1+2i)

= 3+6i-i-2i²

= 3+5i-2(-1)

= 3+5i+2

= 5+5i

Finally, [(3 - i)(3 + i)] [(2 + i)(1 - i)(1 + 2i)]

= 10(5+5i)

= 50+50i

Hence, (3 - i)(3 + i)(2 + i)(1 - i)(1 + 2i) is equivalent to 50+50i

5 0

3 years ago

What is the first quartile and third quartile of this data set: 34, 34, 36, 39, 50, 41, 45, 47, 40?

o-na [289]

Answer:

whatever

Step-by-step explanation:

the first quartile is between 34 and 36 = 35

the third quartile is between 45 and 47 = 46

5 0

3 years ago

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4?

Ludmilka [50]

Answer:

the answer is 77a8b7

Step-by-step explanation:

5 0

3 years ago