The optimum shape of such a box is half a cube. The corresponding cube will have a volume of 2×256 ft³ = 512 ft³ = (8 ft)³. Such a box has a square base that is 8 ft on a side. If the height is half that of the cube, it will be 4 ft.
The dimensions of your box will be 8 ft square by 4 ft high.
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If the base dimension is x ft, the area (quantity of material) is
... a = x² + 4x(256/x²)
... a = x² + 1024x⁻¹
Then the derivative of area with respect to x is
... a' = 2x -1024x⁻²
Setting this derivative to zero and solving for x gives the value of x for minimum area.
... 0 = 2x -1024/x²
... 512 = x³
... x = 8 . . . . . . . . same as above.
Answer:
Hi there
The formula is
A=p (1+r)^t
A future value
P present value
R interest rate
T time
A) A=2,000×(1+0.04)^(3)=2,249.728
B) A=2,000×(1+0.04)^(18)=4,051.63
C) 2500=2000 (1+0.04)^t
Solve for t
T=log(2,500÷2,000)÷log(1+0.04)
T=5.7 years
D) t=log(3,000÷2,000)÷log(1+0.04)
t=10.3 years
Hope it helps
Step-by-step explanation:
Step-by-step explanation:
y=-3+5x
substitute y into equation 2
3x-8y=24
3x-8(-3+5x)=24
3x+24-40x=24
x=0
y=-3+5(0)
y=-3
(x,y)=(0,3)
Hi,
New temperature will be 31 F - 15 F = 16 F.
Green eyes.
Answer:
Third option: 12x^2+8x+25
Step-by-step explanation:
s1=8x^2
s2=4x^2+15
s3=8x+10
Total perimeter of the pool edge: P
P=s1+s2+s3
Replacing s1, s2 and s3 in the formula above:
P=(8x^2)+(4x^2+15)+(8x+10)
P=8x^2+4x^2+15+8x+10
Adding like terms:
P=12x^2+8x+25
