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dlinn [17]
3 years ago
15

What is cold source of light

Chemistry
2 answers:
Anettt [7]3 years ago
6 0
Fireflies. LED, fluorescent light
jekas [21]3 years ago
4 0

Answer:

LEDs (they can heat up, but they do not require heat to emit light, usually heat is an unwanted effect)

Light-emitting field-effect transistors (same consideration as for LEDs)

Fluorescent lighting and generally cold plasmas that can emit light.

Old TV and PC monitors (ie cathode ray tube screen - although the light emission itself does not require heat, the cathode itself that shoots the electrons does)

Chemo-luminescence (like fluorescent sticks)

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Wind ,ice,and water eroded it over years
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3 years ago
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What's the force between two moving objects that are touching called
m_a_m_a [10]
I think it is friction.
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A nucleus emits an alpha particle. What happens to the mass
babunello [35]

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the mass number decreases by 4 and the atomic number decreases by 2

4 0
3 years ago
Calculate the time needed for a constant current of 0.961 a to deposit 0.500 g of co(ii) as
Vera_Pavlovna [14]

1.70 × 10³ seconds

<h3>Explanation </h3>

\text{Co}^{2+} + 2 e⁻ → \text{Co}

It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.

Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains 0.500 / 58.933 = 8.484\times 10^{-3} \; \text{mol} of Co atoms. It would take 2 \times 8.484 \times 10^{-3} = 0.01697 \; \text{mol} of electrons to reduce cobalt (II) ions and produce the 8.484\times 10^{-3} \; \text{mol} of cobalt atoms.

Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of 1.637 \times 10^{3} \; \text{C}. A current of 0.961 A delivers 0.961 C of charge in one single second. It will take 1.637 \times 10^{3} / 0.961 = 1.70 \times 10^{3} \; \text{s} to transfer all these charge and deposit 0.500 g of Co.

4 0
3 years ago
If a gas has a volume of 750 mL at 25°c, what would the volume of the gas be at 55°c?
Airida [17]

825.5mL

To find this, use the equation \frac{V1}{T1} = \frac{V2}{T2}

Make sure to convert all temperatures in Celsius to Kelvin by adding 273. Once you do that, multiply and divide accordingly to get the final answer of 825.5mL

Hope this helps!

4 0
3 years ago
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