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3 years ago

An ioc occurs when what metric exceeds its normal bounds?.

Chemistry

1 answer:

IRISSAK [1]3 years ago

6 0

An ionic bond is formed when there are more or less electrons that normal in bonding atoms.

<h3>What are Ionic bonds?</h3>

An ionic bond is formed when one atoms donates electrons to another specie to form an ion pair. One atom is positively charged while the other specie is negatively charged.

Hence, an ionic bond is formed when there are more or less electrons that normal in bonding atoms.

Learn more about ionic bonds: brainly.com/question/14484184

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which of the following requires the most energy to break a bond? a. breaking cl-br bond. b. breaking a n-p bond. c. breaking a o

irina1246 [14]

A. Breaking a Cl-Br bond

6 0

3 years ago

At a consent tempture the pressure on a 2.5 l ballon is increased from 2.4 atm to 5.8 atm. what is the new volume?

marissa [1.9K]

Answer:

1.034 L

Explanation:

P1 V1 = P2 V2

P1 V1 / P2 = V2

2.4 (2.5) / 5.8 = V2 = 1.034 L

8 0

2 years ago

How many grams of phosphorus are in a sample of Ca3(PO4)2 that contains 50.0 g of calcium? Answer: ________ grams of phosphorus.

wel

<u>Answer:</u> The mass of phosphorus that is present for given amount of calcium is 28.53 g.

<u>Explanation:</u>

We are given:

Mass of calcium = 50 grams

The chemical formula of calcium phosphate is $Ca_3(PO_4)_2$

Molar mass of calcium = 40 g/mol

Molar mass of phosphorus = 31 g/mol

In 1 mole of calcium phosphate, 120 grams of calcium is combining with 62 grams of phosphorus.

So, 50 grams of calcium will combine with = $\frac{62}{120}\times 50=28.53g$ of phosphorus.

Hence, the mass of phosphorus that is present for given amount of calcium is 28.53 g.

6 0

3 years ago

How many Molecules does CH4 Have

valentinak56 [21]

Answer:

The amount of molecules in CH4, also known about methane is simply 0.85 * 6.02210 * 10^23 This amounts to about 5.1 * 10^23

4 0

4 years ago

What is the mass of 3.04×10^-4 mol of baking soda, NaHCO3?

Zigmanuir [339]

Answer:

0.025536g

Explanation:

no. of mole = mass/Mr

mass = Mr × no. of mole

= [23 + 1 + 12 + 3(16)] × 3.04×10^-4

= 0.025536g

= 0.0255g (3 significant figures)

8 0

3 years ago